mysql每小时查询平均值

以下查询从我的水族馆数据库中获取温度，外部温度，pH和总悬浮固体，并将其显示在下表所示的1个表格中。每个值都存储在它自己的表中，并且每分钟记录一次。mysql每小时查询平均值

我想更改下面的查询，以便能够获得每小时的平均值，而不是在x时间显示存储在数据库中的值：00：00。

请帮

SELECT DATE_FORMAT(timeTable.minuteTime, '%Y-%m-%d %k:%i') time, 
oT2.temperature temperature, 
T2.temperature temp, 
S2.solids solids, 
P2.Ph Ph 
FROM 
(
    SELECT minuteTime.minuteTime minuteTime, 
    (SELECT MAX(time) FROM outside_temperature WHERE time <= minuteTime.minuteTime AND time >= NOW() - INTERVAL 1 DAY) otempTime, 
    (SELECT MAX(time) FROM temperature1 WHERE time <= minuteTime.minuteTime AND time >= NOW() - INTERVAL 1 DAY) tempTime, 
    (SELECT MAX(time) FROM Ph WHERE time <= minuteTime.minuteTime AND time >= NOW() - INTERVAL 1 DAY) phTime, 
    (SELECT MAX(time) FROM solids WHERE time <= minuteTime.minuteTime AND time >= NOW() - INTERVAL 1 DAY) solidsTime 

    FROM 
    (
     SELECT DATE(time) + INTERVAL (HOUR(time) DIV 2 * 2) HOUR minuteTime 
     FROM Ph 
     WHERE time >= NOW() - INTERVAL 1 DAY AND time <= NOW() 
     UNION SELECT DATE(time) + INTERVAL (HOUR(time) DIV 2 * 2) HOUR 
     FROM solids 
     WHERE time >= NOW() - INTERVAL 1 DAY AND time <= NOW() 
     UNION SELECT DATE(time) + INTERVAL (HOUR(time) DIV 2 * 2) HOUR 
     FROM outside_temperature 
     WHERE time >= NOW() - INTERVAL 1 DAY AND time <= NOW() 
     UNION SELECT DATE(time) + INTERVAL (HOUR(time) DIV 2 * 2) HOUR 
     FROM temperature1 
     WHERE time >= NOW() - INTERVAL 1 DAY AND time <= NOW() 
     GROUP BY 1 
    ) minuteTime 
) timeTable 
LEFT JOIN outside_temperature oT2 ON oT2.time = timeTable.otempTime 
LEFT JOIN temperature1 T2 ON T2.time = timeTable.tempTime 
LEFT JOIN solids S2 ON S2.time = timeTable.solidsTime 
LEFT JOIN Ph P2 ON P2.time = timeTable.phTime 
ORDER BY minuteTime ASC

这是查询的

2013-04-03 22:00 27.12 26.06 139 7.54 
2013-04-04 0:00  27.06 26  142 7.54 
2013-04-04 2:00  26.94 26  142 7.5 
2013-04-04 4:00  26.87 25.94 142 7.5 
2013-04-04 6:00  26.75 25.87 141 7.58 
2013-04-04 8:00  26.87 25.87 141 7.58 
2013-04-04 10:00 26.87 25.87 141 7.58 
2013-04-04 12:00 26.87 25.87 141 7.58 
2013-04-04 14:00 26.69 25.87 144 7.54 
2013-04-04 16:00 26.56 25.81 144 7.58 
2013-04-04 18:00 26.5 25.75 144 7.61 
2013-04-04 20:00 26.81 25.75 144 7.43

来源

2013-04-04 Ossama

这么多的嵌套选择......我的午餐是回来了 – deed02392 2013-04-04 11:30:00

使用

SELECT DATE_FORMAT(timeTable.minuteTime, '%Y-%m-%d %k:%i') time, 
AVG(oT2.temperature) temperature, 
AVG(T2.temperature) temp, 
AVG(S2.solids) solids, 
AVG(P2.Ph) Ph 
......./*YOUR QUERY 
--AT THE LAST 
GROUP BY DATE_FORMAT(timeTable.minuteTime, '%Y-%m-%d %k:%i')

来源

2013-04-04 11:36:19 Santhosh

您的查询结果仍然与我的查询一样。我想要一个查询，首先从我的数据库中的60个单个值中获取一个小时的平均值，然后显示所有其他传感器的每个小时的平均值，即ph温度固体和外部温度 – Ossama 2013-04-05 15:23:44

查询应该使用类似SELECT DATE_FORMAT（x.time，'％Y-％m-％d％H：00：00'），AVG（x.Ph）avg_Ph FROM Ph x其中time> = NOW（） - INTERVAL 1 DAY GROUP BY DATE_FORMAT（x.time，'％Y-％m-％d％H：00：00'）; – Ossama 2013-04-05 15:31:59

mysql每小时查询平均值

回答

相关问题