2015-11-04 84 views
1

在CSV文件我有栏下面我试着用
的CSV文件列计算

$ awk -v FS="\",\"" -v OFS="\",\"" '{$2=sprintf("%.2f",$2*2)}1' file.csv 

改变第二列的值,但某些列包含字符串,它必须保持不变。我知道

"^[0-9][0-9]*$" 

将检查它是否数字,但如何把它在我的命令结合?

FILE.CSV

"sku","NO price","supplierName" 
"sku","3.14","supplierName" 
"sku","3.56","supplierName" 
"sku","4.20","supplierName" 

回答

1

您可以使用:

awk -v FS='","' -v OFS='","' '$2+0 == $2{$2=sprintf("%.2f",$2*2)}1' file.csv 
"sku","NO price","supplierName" 
"sku","6.28","supplierName" 
"sku","7.12","supplierName" 
"sku","8.40","supplierName" 

$2+0 == $2检查可以确保在$2值是数字。

+0

[检查此答案](http://unix.stackexchange.com/questions/131073/awk-printf-number-in-width-and-round-it-up) – anubhava

+0

请发一个新的问题rounding of这个问题的浮点数是识别数字。 – anubhava

+0

谢谢,它工作 – user5507230