下面是BigQuery的标准SQL
如果你希望得到阵列您可以使用下面
#standardSQL
SELECT ARRAY(SELECT name FROM UNNEST(children)) AS names
FROM `yourproject.yourdataset.yourtable`
您可以测试/使用虚拟数据作为
#standardSQL
WITH `yourproject.yourdataset.yourtable` AS (
SELECT [STRUCT<name STRING, gender STRING, age INT64>('abc1','m',12),('xyz1','m',13),('uvw1','f',14)] children UNION ALL
SELECT [STRUCT<name STRING, gender STRING, age INT64>('abc2','f',12),('xyz2','m',13),('uvw2','f',14)]
)
SELECT ARRAY(SELECT name FROM UNNEST(children)) AS names
FROM `yourproject.yourdataset.yourtable`
它玩
输出为
Row names
1 abc1
xyz1
uvw1
2 abc2
xyz2
uvw2
在情况下,如果你期望的字符串
#standardSQL
SELECT (SELECT STRING_AGG(name) FROM UNNEST(children)) AS names
FROM `yourproject.yourdataset.yourtable`
您可以测试/使用相同的虚拟数据
#standardSQL
WITH `yourproject.yourdataset.yourtable` AS (
SELECT [STRUCT<name STRING, gender STRING, age INT64>('abc1','m',12),('xyz1','m',13),('uvw1','f',14)] children UNION ALL
SELECT [STRUCT<name STRING, gender STRING, age INT64>('abc2','f',12),('xyz2','m',13),('uvw2','f',14)]
)
SELECT (SELECT STRING_AGG(name) FROM UNNEST(children)) AS names
FROM `yourproject.yourdataset.yourtable`
和输出现在是
Row names
1 abc1,xyz1,uvw1
2 abc2,xyz2,uvw2
它玩