员工每日出勤时间的明智标准差

Question

我想计算员工明智的每日时间的标准偏差。

以下是该数据帧或CSV我输入：

EmpCode,Date,InTime,OutTime,expetcedIn,expetcedOut 

9889,01-Feb-17,9:34 AM,5:41:00 PM,9:30:00 AM,5:30:00 PM 

如何去了解它在Python？

Answer 1

我希望你想要的是每个客户每天的工作时间得到s.d。

import pandas as pd 

# Read csv and parses col[1,2] as InTimeWithDate and col[1,3] as OutTimeWithDate 
df=pd.read_csv("emp.csv", parse_dates={"InTimeWithDate":[1,2],"OutTimeWithDate":[1,3]}) 

# Gets difference between In and out time in minutes : to get in seconds changed timedelta64[m] to timedelta64[s] 
df["minutes_worked"]= (df["OutTimeWithDate"]-df["InTimeWithDate"]).astype('timedelta64[m]') 

# Groups by employee and gets standard diff of minutes worked 
new_df = df.groupby("EmpCode").agg({"minutes_worked":["std"]}) 
print(new_df)