如何对变量中的整数进行排序？

Question

Please note that this is on Python 3.3

下面是代码：

students=int(input("How many student's score do you want to sort? ")) 
options=input("What do you want to sort: [Names with scores] , [Scores high to low] , [Scores averages] ? ") 
options=options.upper() 

if options == ("NAMES WITH SCORES") or options == ("NAME WITH SCORE") or options == ("NAME WITH SCORES") or options == ("NAMES WITH SCORE"): 
    a=[] 
    for i in range(0,students): 
     name=input("Enter your scores and name: ") 
     a.append(name) 

    a.sort() 
    print("Here are the students scores listed alphabetically") 
    print(a) 

if options == ("SCORES HIGH TO LOW") or options == ("SCORE HIGH TO LOW"): 
    b=[] 
    number=0 
    for i in range(0,students): 
     number = number+1 
     print("Student "+str(number)) 
     name2=int(input("Enter your first score: ")) 
     name3=int(input("Enter your second score: ")) 
     name4=int(input("Enter your third score: ")) 

     b.append(name2) 
     b.append(name3) 
     b.append(name4) 

    final_score = name2 + name3 + name4 
    print (final_score) 
    b.sort(final_score) 
    print("Student "+str(number)) 
    print(b) 

这里是代码的结果：

>>> 
How many student's score do you want to sort? 2 
What do you want to sort: [Names with scores] , [Scores high to low] , [Scores averages] ? scores high to low 
Student 1 
Enter your first score: 1 
Enter your second score: 2 
Enter your third score: 3 
Student 2 
Enter your first score: 3 
Enter your second score: 5 
Enter your third score: 6 
14 
Traceback (most recent call last): 
    File "H:\GCSE Computing\Task 3\Task 3.py", line 31, in <module> 
    b.sort(final_score) 
TypeError: must use keyword argument for key function 
>>> 

我想要的代码中加入了学生和排序的三个分数学生的总分数，以及相应的名称。

例如： （2名学生）

学生1

• 分数1 - 2
• 分数2 - 4
• 评分3 - 7

（因此总数是13）

学生2

• 分数1 - 5
• 分数2 - 1
• 分数3 - 4

（因此总是10）

（为了从最高到最低的程序打印）“学生1 - 15，学生2 - 10”

Answer 1

您需要使用语法key=final_score传递功能时，排序：

b.sort(key=final_score)

但那种方法需要一个function在传递不可变所以从添加name2 + name3 + name4传递int值是不会吨工作。

如果你只是想整理简单地调用得分列表b.sort()

你应该在列表中使用defautdict并使用每个名称作为键，存储所有的分数做：

from collections import defaultdict 


d = defaultdict(list) 

for _ in range(students): 
    name = input("Enter your name: ") 
    scores = input("Enter your scores separated by a space: " 
    # add all scores for the user to the list 
    d[name].extend(map(int,scores.split())) 

要显示平均，总和最大实在是小巫见大巫：

# from statistics import mean will work for python 3.4 

for k,v in d.items(): 
     print("Scores total for {} is {}".format(k,sum(v))) 
     print("Scores average for {} is {}".format(k,sum(v)/len(v))) # mean(v) for python 3,4 
     print("Highest score for {} is {}".format(k, max(v))) 

打印由最高的用户总得分排序：

print("The top scoring students from highest to lowest are:") 
for k,v in sorted(d.items(),key=lambda x:sum(x[1]),reverse=True): 
    print("{} : {}".format(k,sum(v))) 

现在你有一个字典，学生的名字是关键，每个学生的成绩都存储在一个列表中。

真的，你应该添加一个尝试/除了采取用户输入，并验证它是在正确的格式。