选择和计算结果群里今天和本周日是

Question

我目前有：

SELECT *, COUNT(*) AS counter 
FROM Events 
WHERE TO_DAYS(EventDate) - TO_DAYS(NOW()) >= 7; 
ORDER BY EventDate 

但我想要做的是只计算结果即将推出，并显示有多少是今天有多少在当前一周中，不是7天，而是实际的周一至周日工作周。这是可能的1查询？

Answer 1

SELECT *, (
      SELECT COUNT(*) FROM events WHERE WEEK(EventDate) = WEEK(NOW()) 
     ) as counter 
FROM events 
ORDER BY EventDate 

试试这个，希望它会选择所有的信息，然后作为子查询计算一周的总事件。