我有这样一个JSON格式通过Ajax调用显示JSON数据
{
"user_page_id":"36",
"user_page_name":"yahoo",
"page_template_name":"",
"page_avatar":"false",
"page_address":" Yahoo Pvt Limited,Yahoo CORP,US",
"page_country":"US",
"page_city":"Newyork",
"page_pincode":"22222222223",
"page_email":"[email protected]",
"page_mob":"34654564654",
"page_landline":"235449898544584",
"page_profile":"yes",
"page_meta_tags":" yahoo,yahoo,yahoo",
"page_facebook_username":"yahoo",
"page_twitter_link":"yahoo",
"page_state":"Newyork state"
}
回来,这是我的电话
$.get(url,{parameters},function(data){
alert(data.user_page_name); //return undefined
});
我怎样才能获得的user_page_name
和其他人的价值?
谢谢。
注:The Question is SOLVED
你需要指定JSON作为返回类型 –
@Pekka,waaav,'SOLVED',我忘了和搜索很多...谢谢。 – Red
$ .getJSON为赢 – Sinetheta