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继续阅读本书如何像计算机科学家一样思考。有一段代码不起作用 - 函数内部的变量不会从外部获取(NameError:name'suma'未定义)。我想这个问题可能与回报声明有关,而回报声明似乎与手册相一致。从函数返回(不工作在教程代码上)
有云:
class Time:
pass
time1=Time()
time1.hours=11
time1.minutes=58
time1.seconds=30
time2=Time()
time2.hours=11
time2.minutes=59
time2.seconds=30
def TimePrint(p):
print( int(p.hours), ":" , int(p.minutes) , ":" , int(p.seconds) )
print()
# add these two times. Taken from the book, doesnt work though
def addTime(t1, t2):
suma = Time()
suma.hours = t1.hours + t2.hours
suma.minutes = t1.minutes + t2.minutes
suma.seconds = t1.seconds + t2.seconds
if suma.seconds >= 60:
suma.seconds = suma.seconds - 60
suma.minutes = suma.minutes + 1
if suma.minutes >= 60:
suma.minutes = suma.minutes - 60
suma.hours = suma.hours + 1
return suma
TimePrint(suma)
我可以问一个帮助?我100%肯定缩进到位。
TimePrint(更新时间(时间1,时间2)) –
'suma'是defind在本地的addTime''的范围,而不是外界 – WhatsThePoint
WhatsThePoint可见:是的,我也觉得所以。但我没有足够的经验来了解解决方案。 – Jewenile