用于继承的C++构造函数

Question

我只想检查以便从父类继承构造函数，这是通过使用对象组合来完成它的正确方法吗？

我得到这个错误，他们都指的是我的构造函数。

C:\Users\user\AppData\Local\Temp\cc0CYtVR.o:SquareImp.cpp:(.text+0x16): undefine 
d reference to `vtable for Square' 
C:\Users\user\AppData\Local\Temp\cc0CYtVR.o:SquareImp.cpp:(.text+0x79): undefine 
d reference to `vtable for Square' 
C:\Users\user\AppData\Local\Temp\cc0CYtVR.o:SquareImp.cpp:(.text$_ZN6SquareD1Ev[ 
Square::~Square()]+0xb): undefined reference to `vtable for Square' 
collect2: ld returned 1 exit status 

对不起，这是我的，因为我做了尝试重写他们

ShapeTwoD.h

class ShapeTwoD 
{ 
    protected: 
     string name, warpSpace; 
     bool containsWarpSpace; 
     int xCord, yCord, length, breath; 
    public: 
     //constructor 
     ShapeTwoD(); 
     ShapeTwoD(string, bool); 
}; 

ShapeTwoD.cpp

ShapeTwoD::ShapeTwoD() 
{ 
    string name = ""; 
    bool containsWarpSpace = true; 
} 

ShapeTwoD::ShapeTwoD(string ShapeName, bool warpspace) 
{ 
    name = ShapeName; 
    containsWarpSpace = true; 
} 

square.h

新的脚本

class Square:public ShapeTwoD 
{ 
    private: 
     int xVal,yVal; 
     int newlength, newbreath; 
     double area; 

    public: 
     Square(); 
     Square(string, bool, int, int); 
}; 

square.cpp

Square::Square() 
{ 
    xVal = 0; 
    yVal = 0; 
} 

    Square::Square(string ShapeName, bool warpspace, int xval, int yval):ShapeTwoD(ShapeName, warpspace), xVal(xval), yVal(yval) 
    { 
    xVal = xval; 
    YVal = yval; 
    cout << "test test" << endl; 
} 

int main() 
{ 
    Square square; 
    cout << "hello world" << endl; 
} 

Answer 1

是的，也把xVal和yVal在初始化列表中太：

Square::Square(string ShapeName, bool square, int xval, int yval): 
     ShapeTwoD(ShapeName, square), xVal(xval), yVal(yval) 
{ 
} 

，构建基类Square()太：

Square::Square() : ShapeTwoD(..., ...) 
{ 
}