Break while while循环并转到if/else

Question

我有问题要打开while循环并从while循环的开始处开始。我想循环检查连续检查时间是否等于59秒，如果不去while循环检查日志文件。内部while循环只能在日志文件中找到特定的内容时执行某些操作。

编辑：新脚本。问题是，while循环不运行，不回去，在其他环

脚本再次调用该函数的功能：

#!/bin/bash  

counterSearch=0 
counterIssue=0 
counterPassed=0 
counterFailed=0 
counterSearchPassed=0 
counterSearchFailed=0 
counterIssuePassed=0 
counterIssueFailed=0 
counterTotal=0 
counterHourly=0 
counterAddHourly=0 
declare -a hourlyScan=('6' '0' '5' '0' '7' '2' '0' '13' '0' '18' '0' '0' '7' '0' '6' '0' '0' '1' '3' '0' '0' '0' '3' '0')  

function readLogFile {  

tail -n0 $logJira | \ 
while read line ; do  

    if echo "$line" | grep -e "/rest/api/2/search.*PASSED" 1>/dev/null 2>&1 ; then 
     echo "$date - Search and passed API action" >> $logIng 
     counterSearch=$((counterSearch+1)) 
     counterPassed=$((counterPassed+1)) 
     counterHourly=$((counterHourly+1)) 
     counterTotal=$((counterTotal+1)) 
     echo "$date - Total Passed API Authentication: $counterPassed" >> $logIng 
     echo "$date - Total search API actions: $counterSearch" >> $logIng 
     continue 2  

    elif echo "$line" | grep -e "/rest/api/2/search.*FAILED" 1>/dev/null 2>&1 ; then 
     echo "$date - Search and failed API action" >> $logIng 
     counterSearch=$((counterSearch+1)) 
     counterFailed=$((counterFailed+1)) 
     counterHourly=$((counterHourly+1)) 
     counterTotal=$((counterTotal+1)) 
     echo "$date - Total Failed API Authentication: $counterFailed" >> $logIng 
     echo "$date - Total search API actions: $counterSearch" >> $logIng 
     continue 2  

    elif echo "$line" | grep -e "/rest/api/2/issue.*PASSED" 1>/dev/null 2>&1 ; then 
     echo "$date - Issue and Passed API action" >> $logIng 
     counterIssue=$((counterIssue+1)) 
     counterPassed=$((counterPassed+1)) 
     counterHourly=$((counterHourly+1)) 
     counterTotal=$((counterTotal+1)) 
     echo "$date - Total Passed API Authentication: $counterPassed" >> $logIng 
     echo "$date - Total issue API actions: $counterIssue" >> $logIng 
     continue 2  

    elif echo "$line" | grep -e "/rest/api/2/issue.*FAILED" 1>/dev/null 2>&1 ; then 
     echo "$date -Issue and Failed API action" >> $logIng 
     counterIssue=$((counterIssue+1)) 
     counterFailed=$((counterFailed+1)) 
     counterHourly=$((counterHourly+1)) 
     counterTotal=$((counterTotal+1)) 
     echo "$date - Total Failed API Authentication: $counterFailed" >> $logIng 
     echo "$date - Total issue API actions: $counterIssue" >> $logIng 
     continue 2 
    fi 
done 
}  

function runner { 
while true; do 
currentMinute=$(date +%S) 
currentHour=$(date +%k) 
currentDay=$(date +%u) 
currentWeek=$(date +%W) 
    if [[ $currentMinute -eq 59 ]]; then 
    if [[ ${#hourlyScan[@]} -eq 24 ]]; then 
     unset hourlyScan[23] 
     hourlyScan=($counterHourly "${hourlyScan[@]}") 
     counterHourly=0  

     for i in "${!hourlyScan[@]}"; do 
      $cliScript --server $cliServer --user $cliUser --password $cliPass --action modifyPage --space "VEN" --title "API Usage Monitoring" \ 
      --findReplaceRegex "<tr><td>$i</td><td>(\d*)</td></tr>:<tr><td>$i</td><td>${hourlyScan[$i]}</td></tr>" 
     done 
    fi 
    else 
    readLogFile 
    fi 
done 
}  

runner 

Answer 1

你的尾巴显示最后0线。所以你的$line是空的。

尾-n0

你应该remplace此零值

实例：

> tail -n20 file.txt #display last 20 lines of file.txt 

-n，--lines = K输出的最后K行，而不是最近10次的默认值;或者，使用“-n + K”输出以Kth开头的行。

再次编辑：如果您想阅读完整的文件，有我的方式做到这一点

while read line 
do 
    echo -e "$line\n" 
done < file.txt 

Answer 2

我想你需要的是在内环一break。成像我的虚拟实例反映你想要做什么：

#!/bin/bash 

while true; 
do 
    echo done 
    sleep 
    count=0 
    while true; 
    do 
    count=$(($count + 1)) 
    echo $count 
    if [ $count == "100" ]; then 
     break 
    fi 
    done 
    continue 
done 

这将停止在100计数并进入第一循环的开始。