如何在laravel中的多个关联表中调用5.2

Question

我正面临一个问题。谁能帮我 首先，我有两个型号

1）user.php的

enter code here 
public function listings(){ 
    return $this->hasOne('App\Listing','user_id') 
      ->with("topservices"); 
} 

现在我有上市型号

2）（Listing.php）

enter code here 
public function topservices(){ 
    return $this->hasMany('App\Sellerprofile','list_id'); 
} 

现在我有一个功能

enter code here 
public function nails(){ 
    $users = DB::table('users') 
     ->where(['service_name'=>"Seller"]) 
     ->get(); 
    $users = json_decode(json_encode($users),true); 
    foreach($users as $alluser){ 
     $ids[] = $alluser['id']; 
    } 
    if(!empty($ids)){ 
      $allData = User::with('listings')->whereIn('id',$ids)->get(); 
      $allData = json_decode(json_encode($allData),true); 
      echo "<pre>"; print_r($allData); die; ///when i print this array it gives me below output 

    } 
    $title = "Nails"; 
    return view("listings.listing",['allData'=>$allData,'title'=>$title]); 
} 

输出：

enter code here 
Array 
(
[0] => Array 
    (
     [id] => 1 
     [title] => Mr 
     [firstname] => kunal 
     [email] => kunal@gmail.comsc 
     [listings] => Array 
      (
       [id] => 1 
       [user_id] => 1 
       [type] => premimum 
       [business_name] => kunal 
       [topservices] => Array 
        (
         [0] => Array 
          (
           [id] => 5 
           [service_id] => 1 
           [list_id] => 1 
           [name] => Acrylic 
           [duration] => 10mins 
           [price] => 10 
          ) 

         [1] => Array 
          (
           [id] => 6 
           [service_id] => 2 
           [list_id] => 1 
           [name] => Hair Top 
           [duration] => 30mins 
           [price] => 20 
          ) 

         [2] => Array 
          (
           [id] => 7 
           [service_id] => 3 
           [list_id] => 1 
           [name] => Skin Care Top 
           [duration] => 1hr-30mins 
           [price] => 30 
          ) 

         [3] => Array 
          (
           [id] => 8 
           [service_id] => 4 
           [list_id] => 1 
           [name] => Massage Top 
           [duration] => 20mins 
           [price] => 50 
          ) 

        ) 
      ) 

    ) 

[1] => Array 
    (
     [id] => 2 
     [title] => Mr 
     [firstname] => kunal 
     [email] => kunal@gmail.comsdsfd 
     [listings] => Array 
      (
       [id] => 2 
       [user_id] => 2 
       [type] => premimum 
       [topservices] => Array 
        (
         [0] => Array 
          (
           [id] => 9 
           [service_id] => 6 
           [list_id] => 2 
           [name] => Acrylic 
           [duration] => 30mins 
           [price] => 10 
          ) 

         [1] => Array 
          (
           [id] => 10 
           [service_id] => 6 
           [list_id] => 2 
           [name] => Powder gel nails 
           [duration] => 45mins 
           [price] => 20 
          ) 

         [2] => Array 
          (
           [id] => 11 
           [service_id] => 6 
           [list_id] => 2 
           [name] => Polish change 
           [duration] => 10mins 
           [price] => 25 
          ) 

         [3] => Array 
          (
           [id] => 12 
           [service_id] => 6 
           [list_id] => 2 
           [name] => Hand design 
           [duration] => 2hrs 
           [price] => 100 
          ) 

         [4] => Array 
          (
           [id] => 13 
           [service_id] => 7 
           [list_id] => 2 
           [name] => Hair Top 
           [duration] => 30mins 
           [price] => 200 
          ) 

        ) 
      ) 

    ) 
) 

现在你上面的输出看到有Topservices阵列我想下topservices其价格大于等于比= 10，少到30 我的预期成果是所有这些阵列： -

enter code here 
Array 
(
[0] => Array 
    (
     [id] => 1 
     [title] => Mr 
     [firstname] => kunal 
     [email] => kunal@gmail.comsc 
     [listings] => Array 
      (
       [id] => 1 
       [user_id] => 1 
       [type] => premimum 
       [business_name] => kunal 
       [topservices] => Array 
        (
         [0] => Array 
          (
           [id] => 5 
           [service_id] => 1 
           [list_id] => 1 
           [name] => Acrylic 
           [duration] => 10mins 
           [price] => 10 
          ) 

         [1] => Array 
          (
           [id] => 6 
           [service_id] => 2 
           [list_id] => 1 
           [name] => Hair Top 
           [duration] => 30mins 
           [price] => 20 
          ) 
        ) 
      ) 

    ) 

[1] => Array 
    (
     [id] => 2 
     [title] => Mr 
     [firstname] => kunal 
     [email] => kunal@gmail.comsdsfd 
     [listings] => Array 
      (
       [id] => 2 
       [user_id] => 2 
       [type] => premimum 
       [topservices] => Array 
        (
         [0] => Array 
          (
           [id] => 9 
           [service_id] => 6 
           [list_id] => 2 
           [name] => Acrylic 
           [duration] => 30mins 
           [price] => 10 
          ) 

         [1] => Array 
          (
           [id] => 10 
           [service_id] => 6 
           [list_id] => 2 
           [name] => Powder gel nails 
           [duration] => 45mins 
           [price] => 20 
          ) 

         [2] => Array 
          (
           [id] => 11 
           [service_id] => 6 
           [list_id] => 2 
           [name] => Polish change 
           [duration] => 10mins 
           [price] => 25 
          ) 

        ) 
      ) 

    ) 
) 

任何人都可以帮助我。在此先感谢我所做的指甲功能

Answer 1

在这里，我找到了我自己的解决方案。

enter code here 
$allData = User::with(['listings.topservices'=>function($query){ 
      $query->whereBetween('price',[10,350]); 
      }]) 
      ->whereIn('id',$ids)->get(); 

Answer 2

您可以更改您的方法以包括条件。
您可以使用whereBetween方法：

public function listings($lowerPriceLimit = null,$upperPriceLimit = null){ 
    $query = $this->hasOne('App\Listing','user_id'); 
    if($lowerPriceLimit != null && $upperPriceLimit != null) 
     $query = $query->with(["topservices"=>function($q) use($lowerPriceLimit,$upperPriceLimit){ 
          $q->whereBetween('price',[$lowerPriceLimit,$upperPriceLimit]); 
         }]); 
    else 
     $query->with("topservices"); 
    return $query; 
}