如何使用onClick与angularJs？

Question

我已经写了条件

onclick="window.open({{video_call_url}}, '_system', 'location=yes'); return false;" 

这里video_call_url在myController的definded为$scope.video_call_url = 'http://www.google.com/';

但是当我按一下按钮我得到一个错误video_call_url is not defined.

Answer 1

你可以做逻辑控制器：

function myController($scope, $window) { 
    $scope.openVideoCallUrl = function() { 
     $window.open($scope.video_call_url, "_system", "location=yes"); 
     return false; 
    } 
} 

而在你看来

<a ng-click="openVideoCallUrl()">Open!</a> 

Answer 2

你可以使用ng-click，而是采用onclick

ng-click="open(video_call_url)" 

$scope.open = function(url) { 
    //inject $window inside controller. 
    $window.open(url, '_system', 'location=yes'); 
    return false; 
}