如何获取引起异常的函数的参数

Question

可以说，我下面的代码：

def myDecorator(func): 
    def wrapper(self): 
    try: 
     func(self) 
    except Exception as e: 
     print "The argument of the function was:" # print "Some Text" 
     raise 
    wrapper.__name__ = funct.__name__ 
    return wrapper 


@myDecorator 
def do_something(self): 
    do_something_again("Some text") 

我的问题是：我怎样才能显示它是考虑到功能“do_something_again”我里面“的说法除了“块？

Answer 1

打印str(e)获取附加信息。示例在您的情况下：

def myDecorator(func): 
    def wrapper(self): 
    try: 
     func(self) 
    except Exception as e: 
     print "The argument of the function was:", str(e) 
     raise 
    wrapper.__name__ = funct.__name__ 
    return wrapper