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余米使用KSOAP。但我发现了以下错误调用PHP Web服务如何在android中调用php webseviece?
org.xmlpull.v1.XmlPullParserException: expected: START_TAG {http://schemas.xmlsoap.org/soap/envelope/}Envelope (position:START_TAG <root>@1:47 in [email protected])
在m改变我的名字空间和动作名称它给结束标记的错误plz帮助我米,我的工作和填充有罪感到困惑ABT这个简单problem.help我..
String NAMESPACE = "http://www.abc.com/abc";
//String URL = " http://local/abc_webservice/webservice.php?op=login";
//String SOAP_ACTION = "http://local/abc_webservice/webservice.php/login";
//String METHOD_NAME = "login"
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
request.addProperty("edtUserEmailValue",edtemailid.getText().toString());
request.addProperty("edtUserPasswordValue",edtpaswword.getText().toString());
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet = true;
envelope.setOutputSoapObject(request);
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
androidHttpTransport.call(SOAP_ACTION, envelope);
SoapObject resultsRequestSOAP = (SoapObject) envelope.bodyIn;
SoapObject loginValue =(SoapObject)resultsRequestSOAP.getProperty(0);
result=loginValue.getProperty("Result").toString();
EmailAddress=loginValue.getProperty("EmailAddress").toString();
String res1="Success";
if(result.equals(res1)){
UserID =Integer.parseInt(loginValue.getProperty("UserID").toString());
startActivity(new Intent(Sign.this,Peoplynearby.class));
}else{
displayAlert();
}
//Toast.makeText(getBaseContext(), loginValue,Toast.LENGTH_LONG).show();
}catch(NumberFormatException e){
//Toast.makeText(getBaseContext(),e.toString(),Toast.LENGTH_SHORT).show();
}catch(Exception e){
e.printStackTrace();
//Toast.makeText(getBaseContext(),e.toString(),Toast.LENGTH_SHORT).show();
}
在m调试谈到对resultRequestsoap应用它提供了以下错误org.xmlpull.v1.XmlPullParserException: expected: START_TAG {http://schemas.xmlsoap.org/soap/envelope/}Envelope (position:START_TAG <root>@1:47 in [email protected])
请检查您的命名空间,METHODNAME从WSDL和也正确的网址获得价值与否。 – 2011-05-04 06:23:55