2
我有2所列出:如何打印2个列表循环?
filtered_items_list = [src1, scr2, scr3]
filtered_items_url_list = [url1, url2, url3]
我需要打印的
src1, url1
src2, url2
src3, url3
如果我尝试:
>>> for src, url in filtered_items_list, filtered_items_url_list:
print src, url
我得到这个错误:
ValueError: too many values to unpack
如果我尝试这样的:
>>> for src in filtered_items_list:
for url in filtered_items_url_list:
print """"src: %s; url: %s""" % (src, url)
我得到这个:
"src: src1; url: url1
"src: src1; url: url2
"src: src1; url: url3
"src: scr2; url: url1
"src: scr2; url: url2
"src: scr2; url: url3
"src: scr3; url: url1
"src: scr3; url: url2
"src: scr3; url: url3
>>>
您能否提供一个解决方案吗?谢谢!
[izip(http://docs.python.org/library/itertools.html#itertools.izip)往往BA更好的选择,因为它避免了不必要的复制名单。请注意,它们都在最短列表的末尾处被切断。如果你想使用最长的`izip_longest()`,它会为剩余的填充None(或其他默认值)。 – chmullig 2011-02-04 17:53:04