因此,我编写了一个模拟骰子游戏的程序,就像骰子游戏一样。我想把这个正常的控制台应用程序变成基于对话框的MFC。所以我会创建一个标签为“Roll”的按钮,并且窗口会显示正在滚动的两个模子。 以下是我为吊app应用程序编写的代码。它完美的工作,但我很困惑如何将代码分配给按钮,以及如何将模具面分配给其各自的位图。我感谢帮助!如何将现有的代码/位图分配给MFC
//Game of chance "Craps"
#include "stdafx.h"
using namespace std;
void dice(void)
{
//variables
string input;
int i,roll,gamePoint,val,val_1,val_2,roll_1,roll_2,sumRoll;
long winnings,losses,wager,odds,oddsNumer,oddsDenom;
bool A=false;
//declarations
roll=0;gamePoint=0;val=0;val_1=0;val_2=0;roll_1=0;roll_2=0;sumRoll=0;
//user input
cout<<"Enter your odds ratio:\nNumerator: ";
cin>>oddsNumer;
cout<<setw(8)<<"Denominator: ";
cin>>oddsDenom;
cout<<"Enter your wager for the game: ";
cin>>wager;
odds=abs((oddsNumer/oddsDenom)+1);
winnings=abs(odds*wager-wager);
cout<<winnings;
//dice output
do
{
srand (unsigned(time(NULL)));
sumRoll=0;
for(i=0;i<2;i++)
{
val_1=rollDice();
//cout<<"***test1***";
switch (val_1)
{//start switch
case 1:
dieFace(val_1);
break;
case 2:
dieFace(val_1);
break;
case 3:
dieFace(val_1);
break;
case 4:
dieFace(val_1);
break;
case 5:
dieFace(val_1);
break;
case 6:
dieFace(val_1);
break;
}//end switch
sumRoll=val_1+sumRoll;
}//end for loop dice roll
cout<<endl<<endl<<"\tYou rolled a: "<<sumRoll<<endl;
system("pause");
if (sumRoll==7 ||sumRoll==11)
{
cout<<"Hurray! You win!\n"<<
"Your total winnings: $"<<winnings<<endl;
A=true;
system("pause");
}//and if winner statement
else if(sumRoll==2 ||sumRoll==3||sumRoll==12)
{
losses=abs(odds*wager);
cout<<"Sorry, you lose. The house wins. Total lost is $"<<
losses<<endl;
A=true;
system("pause");
}
else
{
gamePoint=sumRoll;
roll=0;
do
{
srand (unsigned(time(NULL)));
sumRoll=0;
roll++;
for(i=0;i<2;i++)
{
val_1=rollDice();
switch (val_1)
{//start switch
case 1:
dieFace(val_1);
break;
case 2:
dieFace(val_1);
break;
case 3:
dieFace(val_1);
break;
case 4:
dieFace(val_1);
break;
case 5:
dieFace(val_1);
break;
case 6:
dieFace(val_1);
break;
}//end switch
sumRoll=val_1+sumRoll;
}//end for loop dice roll
cout<<endl<<endl<<"\tYou rolled a: "<<sumRoll<<endl;
system("pause");
if (sumRoll==7)
{
losses=abs(wager*roll*odds);
cout<<"Sorry, you lose. The house wins."<<
"Total lost is $"<<losses<<endl;
A=true;
system("pause");
}
else if(sumRoll==gamePoint)
{
winnings=abs(wager*roll*odds-wager);
cout<<"Hurray! You win!\n"<<
"Your total winnings are $"<<winnings<<endl;
A=true;
system("pause");
}
}while(A==false);
}
}while(A==false);
system("pause");
system("cls");
return ;
}
int rollDice(void)
{
//srand (unsigned(time(0)));
return((rand()%6)+1);
}
void dieFace(int val)
{
switch (val)
{//start switch
case 1:
cout<<endl<<endl<<endl;
cout<<" *************"<<endl;
cout<<" * *"<<endl;
cout<<" * *"<<endl;
cout<<" * O *"<<endl;
cout<<" * *"<<endl;
cout<<" * *"<<endl;
cout<<" *************"<<endl<<endl;
break;
case 2:
cout<<endl<<endl<<endl;
cout<<" *************"<<endl;
cout<<" * O *"<<endl;
cout<<" * *"<<endl;
cout<<" * *"<<endl;
cout<<" * *"<<endl;
cout<<" * O *"<<endl;
cout<<" *************"<<endl<<endl;
break;
case 3:
cout<<endl<<endl<<endl;
cout<<" *************"<<endl;
cout<<" * O *"<<endl;
cout<<" * *"<<endl;
cout<<" * O *"<<endl;
cout<<" * *"<<endl;
cout<<" * O *"<<endl;
cout<<" *************"<<endl<<endl;
break;
case 4:
cout<<endl<<endl<<endl;
cout<<" *************"<<endl;
cout<<" * O O *"<<endl;
cout<<" * *"<<endl;
cout<<" * *"<<endl;
cout<<" * *"<<endl;
cout<<" * O O *"<<endl;
cout<<" *************"<<endl<<endl;
break;
case 5:
cout<<endl<<endl<<endl;
cout<<" *************"<<endl;
cout<<" * O O *"<<endl;
cout<<" * *"<<endl;
cout<<" * O *"<<endl;
cout<<" * *"<<endl;
cout<<" * O O *"<<endl;
cout<<" *************"<<endl<<endl;
break;
case 6:
cout<<endl<<endl<<endl;
cout<<" *************"<<endl;
cout<<" * O O *"<<endl;
cout<<" * *"<<endl;
cout<<" * O O *"<<endl;
cout<<" * *"<<endl;
cout<<" * O O *"<<endl;
cout<<" *************"<<endl<<endl;
break;
}
return ;
}
你是否拥有或有权访问任何有MFC编程窗口的书籍? [“使用MFC编程Windows”](http://www.amazon.com/Programming-Windows-MFC-Second-Edition/dp/1572316950)是一个体面的。 – WhozCraig 2013-04-23 05:23:57
您应该一次解决一个问题。获取为按钮添加的commadn处理程序,并使用静态控件显示结果或活动。一旦完成,继续添加位图。询问这两者将只会使提供工作解决方案变得更加困难。我建议你选择哪一个更重要,并更新你的问题来关注这个问题。 – 2013-04-23 05:25:05