无法解析json - 字符串不能转换为JSONArray

Question

我试图从https://jsonplaceholder.typicode.com/users解析json时遇到问题，在String中获取json响应并移入JSONArray，然后解析它。但是，它说java.lang.String不能转换为JSONArray。

我得到json响应的代码是在doInBackground（）中，解析了onPostExecute（）中的json。

这里是我的解析代码：

public class HomeActivity extends AppCompatActivity { 
    public static final int CONNECTION_TIMEOUT = 10000; 
    public static final int READ_TIMEOUT = 15000; 
    private RecyclerView rv_user; 
    private AdapterUser mAdapter; 

    @Override 
    protected void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.activity_home); 
     new AsyncFetch().execute(); 
    } 

    private class AsyncFetch extends AsyncTask<String, String, String> { 
     String response = ""; 
     ProgressDialog pdLoading = new ProgressDialog(HomeActivity.this); 
     HttpURLConnection conn; 
     URL url = null; 

     @Override 
     protected void onPreExecute() { 
      super.onPreExecute(); 

      pdLoading.setMessage("\tLoading..."); 
      pdLoading.setCancelable(false); 
      pdLoading.show(); 

     } 

     @Override 
     protected String doInBackground(String... params) { 
      try { 
       url = new URL("https://jsonplaceholder.typicode.com/users"); 
      } catch (MalformedURLException e) { 
       e.printStackTrace(); 
       return e.toString(); 
      } 

      try { 
       conn = (HttpURLConnection) url.openConnection(); 
       conn.setReadTimeout(READ_TIMEOUT); 
       conn.setConnectTimeout(CONNECTION_TIMEOUT); 
       conn.setRequestMethod("GET"); 

       conn.setDoOutput(true); 

      } catch (IOException e1) { 
       e1.printStackTrace(); 
       return e1.toString(); 
      } 

      try { 
       int response_code = conn.getResponseCode(); 
       if (response_code == HttpURLConnection.HTTP_OK) { 
        BufferedReader reader = new BufferedReader(new InputStreamReader(conn.getInputStream())); 
        StringBuilder sb = new StringBuilder(); 
        String line; 

        while ((line = reader.readLine()) != null) { 
         sb.append(line); 
        } 
        response = sb.toString(); 

        // Pass data to onPostExecute method 
        System.out.println(response); 

        return (response); 
       } else { 
        return ("unsuccessful"); 
       } 

      } catch (IOException e) { 
       e.printStackTrace(); 
       return e.toString(); 
      } finally { 
       conn.disconnect(); 
      } 
     } 

     @Override 
     protected void onPostExecute(String result) { 
      pdLoading.dismiss(); 
      List<DataUser> data = new ArrayList<>(); 
      pdLoading.dismiss(); 
      try { 
       JSONArray jArray = new JSONArray(result); 
       // Extract data from json and store into ArrayList as class objects 
       for(int i=0;i<jArray.length();i++){ 
        JSONObject json_user_data = jArray.getJSONObject(i); 

        DataUser userData = new DataUser(); 
        userData.id = json_user_data.getString("id"); 
        userData.fullName = json_user_data.getString("name"); 
        userData.uName = json_user_data.getString("username"); 
        userData.email = json_user_data.getString("email"); 

        JSONObject addr = json_user_data.getJSONObject("address"); 
        String street = addr.getString("street"); 
        String city = addr.getString("city"); 
        int zip = addr.getInt("zipcode"); 

        userData.address = street+", "+ city + " " + zip; 
        userData.phone = json_user_data.getString("phone"); 
        userData.web = json_user_data.getString("website"); 
        data.add(userData); 
       } 

       // Setup and Handover data to recyclerview 
       rv_user = (RecyclerView)findViewById(R.id.userList); 
       mAdapter = new AdapterUser(HomeActivity.this, data); 
       rv_user.setAdapter(mAdapter); 
       rv_user.setLayoutManager(new LinearLayoutManager(HomeActivity.this)); 

      } catch (JSONException e) { 
       Toast.makeText(HomeActivity.this, e.toString(), Toast.LENGTH_LONG).show(); 
      } 

     } 

    } 
} 

帮助我，请。谢谢。

Answer 1

变化两个字符串在代码：

conn.setDoOutput(false);
你要阅读从服务器，写不出来。在你的JSON

String zip = addr.getString("zipcode");
邮编有59590-4157形式，因此不能被解读为INT。

Answer 2

你看过网址中“结果”的内容吗？我想这不是你想要的。