如何绘制具有多个数据框的FacetGrid散点图？

Question

我有2个数据框，1个有训练数据，另一个有标签。训练数据中有6个特征/列，标签数据帧中有1列。我想在我的小平面网格中绘制6个图 - 所有这些都是散点图。所以功能1与标签，功能2与标签，功能3与标签，功能4与标签。

有人可以告诉我如何做到这一点？

例如，使用这些采样数据帧

In [15]: training 
Out[15]: 
    feature1 feature2 feature3 feature4 feature5 feature6 
0   2   3   4   5   2   5 
1   5   4   2   5   6   2 

In [16]: labels 
Out[16]: 
    label 
0  34 
1  2 

这应该使6个单独的散点图，每2个数据点。

Answer 1

Seaborn有一个很好的FacetGrid function.You可以合并你的两个dataframes环绕正常matplotlib.pyplot.scatter（）的seaborn facetgrid

import pandas as pd 
import random 
import matplotlib.pyplot as plt 
import seaborn as sns 

#make a test dataframe 
features = {} 
for i in range(7): 
    features['feature%s'%i] = [random.random() for j in range(10)] 
f = pd.DataFrame(features) 
labels = pd.DataFrame({'label':[random.random() for j in range(10)]}) 

#unstack it so feature labels are now in a single column 
unstacked = pd.DataFrame(f.unstack()).reset_index() 
unstacked.columns = ['feature', 'feature_index', 'feature_value'] 
#merge them together to get the label value for each feature value 
plot_data = pd.merge(unstacked, labels, left_on = 'feature_index', right_index = True) 
#wrap a seaborn facetgrid 
kws = dict(s=50, linewidth=.5, edgecolor="w") 
g = sns.FacetGrid(plot_data, col="feature") 
g = (g.map(plt.scatter, "feature_value", "label", **kws))