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我一直在尽我所能去使这个脚本工作，我只是无法弄清楚我做错了什么。我对PHP和Javascript非常陌生，我正在尝试修改我在互联网上发现的脚本，以便在我的网站上获得级联下拉菜单。这是一个相当简单的脚本，不幸的是它不使用AJAX，因此它需要刷新页面，但如果Im遇到困难，我不认为我应该继续使用AJAX。我遇到的问题是脚本应该在页面刷新时从菜单中选择一个棒，但它总是会重置为默认值SELECT ONE。它在原始脚本中工作，但我已经做了很多修改，所以我不知道为什么我不坚持。原来的剧本是：Cascading Drop Down页面刷新
<?php
//***************************************
// This is downloaded from www.plus2net.com //
/// You can distribute this code with the link to www.plus2net.com ///
// Please don't remove the link to www.plus2net.com ///
// This is for your learning only not for commercial use. ///////
//The author is not responsible for any type of loss or problem or damage on using this script.//
/// You can use it at your own risk. /////
//*****************************************
$dbservertype='mysql';
$servername='localhost';
// username and password to log onto db server
$dbusername='';
$dbpassword='';
// name of database
$dbname='dd';
////////////////////////////////////////
////// DONOT EDIT BELOW /////////
///////////////////////////////////////
connecttodb($servername,$dbname,$dbusername,$dbpassword);
function connecttodb($servername,$dbname,$dbuser,$dbpassword)
{
global $link;
$link=mysql_connect ("$servername","$dbuser","$dbpassword");
if(!$link){die("Could not connect to MySQL");}
mysql_select_db("$dbname",$link) or die ("could not open db".mysql_error());
}
//////// End of connecting to database ////////
?>
<!doctype html public "-//w3c//dtd html 3.2//en">
<html>
<head>
<title>Multiple drop down list box from plus2net</title>
<SCRIPT language=JavaScript>
function reload(form)
{
var val=form.cat.options[form.cat.options.selectedIndex].value;
self.location='dd.php?cat=' + val ;
}
</script>
</head>
<body>
<?
/*
If register_global is off in your server then after reloading of the page to get the value of cat from query string we have to take special care.
To read more on register_global visit.
http://www.plus2net.com/php_tutorial/register-globals.php
*/
@$cat=$_GET['cat']; // Use this line or below line if register_global is off
if(strlen($cat) > 0 and !is_numeric($cat)){ // to check if $cat is numeric data or not.
echo "Data Error";
exit;
}
//@$cat=$HTTP_GET_VARS['cat']; // Use this line or above line if register_global is off
///////// Getting the data from Mysql table for first list box//////////
$quer2=mysql_query("SELECT DISTINCT category,cat_id FROM category order by category");
///////////// End of query for first list box////////////
/////// for second drop down list we will check if category is selected else we will display all the subcategory/////
if(isset($cat) and strlen($cat) > 0){
$quer=mysql_query("SELECT DISTINCT subcategory FROM subcategory where cat_id=$cat order by subcategory");
}else{$quer=mysql_query("SELECT DISTINCT subcategory FROM subcategory order by subcategory"); }
////////// end of query for second subcategory drop down list box ///////////////////////////
echo "<form method=post name=f1 action='dd-check.php'>";
/// Add your form processing page address to action in above line. Example action=dd-check.php////
////////// Starting of first drop downlist /////////
echo "<select name='cat' onchange=\"reload(this.form)\"><option value=''>Select one</option>";
while($noticia2 = mysql_fetch_array($quer2)) {
if($noticia2['cat_id'][email protected]$cat)
{echo "<option selected value='$noticia2[cat_id]'>$noticia2[category]</option>"."<BR>";}
else{echo "<option value='$noticia2[cat_id]'>$noticia2[category]</option>";}
}
echo "</select>";
////////////////// This will end the first drop down list ///////////
////////// Starting of second drop downlist /////////
echo "<select name='subcat'><option value=''>Select one</option>";
while($noticia = mysql_fetch_array($quer)) {
echo "<option value='$noticia[subcategory]'>$noticia[subcategory]</option>";
}
echo "</select>";
////////////////// This will end the second drop down list ///////////
//// Add your other form fields as needed here/////
echo "<input type=submit value=Submit>";
echo "</form>";
?>
<center><a href='http://www.plus2net.com'>PHP SQL HTML free tutorials and scripts</a></center>
</body>
</html>
然后我的脚本：
<?php
$dbservertype='mysql';
$servername='localhost';
$dbusername='newuser';
$dbpassword='';
$dbname='supplydb';
connecttodb($servername,$dbname,$dbusername,$dbpassword);
function connecttodb($servername,$dbname,$dbuser,$dbpassword){
global $link;
$link=mysql_connect ("$servername","$dbuser","$dbpassword");
if(!$link){die("Could not connect to MySQL");}
mysql_select_db("$dbname",$link) or die ("could not open db".mysql_error());}
?>
<!doctype html public "-//w3c//dtd html 3.2//en">
<html>
<head>
<title>Multiple drop down list box from plus2net</title>
<SCRIPT language=JavaScript>
function reload(form){
var val=form.category.options[form.category.options.selectedIndex].text;
self.location='dd.php?cat=' + val ;
}
function reload2(form)
{
var val=form.cat.options[form.cat.options.selectedIndex].text;
var val2=form.subcat.options[form.subcat.options.selectedIndex].text;
self.location='dd.php?cat=' + val + '&cat2=' + val2 ;
console.log(val2);
}
</script>
</head>
<body>
<?
////// Grab Get after page refresh
$cat=$_GET['cat'];
$command="SELECT * FROM product_group WHERE type = 1";
$quer2 = mysql_query($command);
if(isset($cat) and strlen($cat) > 1){
$num = explode(' ',$cat);
$number = $num[0];
$strLen = strlen($number);
for ($i = 0; $i < $strLen; $i++)
{$arr[] = $number{$i};}
$arr1 = $arr [0];
$arr2 = $arr [1];
$arr3 = $arr1.$arr2;
$command1="SELECT * FROM `product_group` WHERE `group` LIKE '".$arr3."%' AND type = '2'";
$quer = mysql_query($command1);
}
echo "<form method=post name=category action='dd-check.php'>";
///////////// Create First Drop Down Box
echo "<select name='category' onchange=\"reload(this.form)\"><option value=''>Select one</option>";
while($query = mysql_fetch_assoc($quer2)){
if($query['group']==$cat){
echo "<option selected value='$query[group]'>$query[group]</option>"."<BR>";}
else {echo "<option value='$query[group]'>$query[group]</option>";}
}
echo "</select>";
////////////// Create Second Drop Down Box
echo "<select name='subcat' onchange=\"reload2(this.form)\"><option value=''>Select one</option>";
while($query2 = mysql_fetch_array($quer)){
if($query2['group']==$cat2)
{echo "<option selected value='$query2[group]'>$query2[group]</option>"."<BR>";}
else {echo "<option value='$query2[group]'>$query2[group]</option>";}
}
echo "</select>";
echo "</form>";
print_r ($cat);
?>
</body>
</html>
地指出任何帮助，在我的笨蛋的错误是会有所帮助。提前致谢。
格式化你的代码会很有帮助。你有第一个错误。 – 2011-12-26 01:31:53
对不起，我现在试着修复此问题...... – 2011-12-26 01:41:32
使用空格而不是制表符，并确保每行至少有四个空格。顺便说一句，你不觉得HTML3.2有点老吗？ – 2011-12-26 01:43:10