嵌套类查询和加入

我有以下情况，在这种情况下，我正在寻找拼合嵌套对象，并将父和子字段组合在一行中，而不是创建对象的父和子。嵌套类查询和加入

另外我想结合v1和v2。任何建议？

public class Person 
{ 
    public string idPerson; 
    public string names; 
    private List<Subject> subjects = new List<Subject>(); 
    private List<MedicalRecord> medicalRecords = new List<MedicalRecord>(); 
} 

public class Subject 
{ 
    public string subjectName; 
    public string subjectId; 
} 

public class MedicalRecord 
{ 
    public int recordId; 
    public string doctorName; 
    public string medicalCare; 
} 

void main() 
{ 
    /// Assume that Person is filled. 
    /// How can I join the two lists? 

    List<Person> all = new List<Person>(); 
    var v1 = all.SelectMany(p => p.subjects, (child, parent) => new { child, parent }); 
    var v2 = all.SelectMany(p => p.medicalRecords, (child, parent) => new { child, parent }); /// here i want to select all fields instead of objects to avoid child and parent calling from below cycle. 

    /// I want to join v1 and v2 and flatten the lists. 
    foreach(var obj in v1) 
    { 
     Console.WriteLine(obj.child.subjectName + " " + obj.parent.idPerson); 
    } 

    /// 

}

来源

2016-09-22 jrpz

所以，你要与{人，主题，MedicalRecord}，然而，一个人拥有多学科和医疗记录扁平列表结束，那么分组应该是什么样子？如果受试者多于医疗记录，反之亦然？有其他选择吗？ –

我想加入并扁平al字段，这两个列表中的人员编号为 – jrpz

首先，考虑尝试'var v2 = all.medicalRecords'，因为您无论如何都需要所有字段。为了将它们连接在一起，是否有什么特别的原因可以简单地在'v1.idPerson等于v2.idPerson'上使用linq的'join' –

你需要做如下：

static void Main(string[] args) 
{ 
    List<Person> all = new List<Person>(); 

    // Estract the flattened list of subjects 
    var subjects = all.SelectMany(p => p.Subjects, (person, subject) => new { person.idPerson, person.names, subject}); 
    // Estract the flattened list of medical records 
    var medicalRecords = all.SelectMany(p => p.MedicalRecords, (person, medicalRecord) => new { person.idPerson, person.names, medicalRecord}); 

    // Join the two lists and create a flattened object 
    var flattenedList = 
     subjects.Join(medicalRecords, 
         s => s.idPerson, 
         m => m.idPerson, 
         (s, m) => new { 
          IdPerson = s.idPerson, 
          Names = s.names, 
          s.subject.SubjectId, 
          s.subject.SubjectName, 
          m.medicalRecord.RecordId, 
          m.medicalRecord.DoctorName, 
          m.medicalRecord.MedicalCare 
         }) 
         .ToList(); 
}

来源

2016-09-23 06:52:04 user449689

嵌套类查询和加入

回答

相关问题