我正在创建2个下拉列表，第二个是基于第一个下拉列表的选择。将数据从MySQL数据库中检索php ajax droplist

的index.php

<!DOCTYPE html> 
<html lang="en"> 
    <head> 
     <meta charset="UTF-8" /> 
     <meta http-equiv="X-UA-Compatible" content="IE=edge,chrome=1"> 
     <meta name="viewport" content="width=device-width, initial-scale=1.0"> 
     <title>Playing With Select list</title> 
     <link rel="stylesheet" type="text/css" href="css/demo.css" /> 
     <link href='http://fonts.googleapis.com/css?family=Open+Sans:300,700' rel='stylesheet' type='text/css' /> 
     <!--[if lte IE 8]><style>.main{display:none;} .support-note .note-ie{display:block;}</style><![endif]--> 
    <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script> 
    <script type="text/javascript"> 
     $(document).ready(function() 
     { 
     $(".country").change(function() 
     { 
     var id=$(this).val(); 
     var dataString = 'id='+ id; 

     $.ajax 
     ({ 
     type: "POST", 
     url: "ajax_category.php", 
     data: dataString, 
     cache: false, 
     success: function(html) 
     { 
     $(".governorate").html(html); 
     } 
     }); 

     }); 
     }); 
    </script> 

    </head> 
    <body> 
     <div class="container"> 
      <header> 
       <h1><strong>Playing With Select List</strong></h1> 
       <h2>Select One List To see Output On Other</h2> 
      </header> 
     </div> 
    <span style="margin-left:22%"> 
      <label>country :</label> <select name="country" class="category"> 
<option selected="selected">--Select Country--</option> 
<?php 
include('db.php'); 
$sql=mysql_query("select country_id,country_name from country"); 
while($row=mysql_fetch_array($sql)) 
{ 
$id=$row['country_id']; 
$data=$row['country_name']; 
echo '<option value="'.$id.'">'.$data.'</option>'; 
} ?> 
</select> &nbsp;&nbsp;&nbsp; 
<label>Governorate :</label> <select name="governorate" class="subcategory"> 
<option selected="selected">--Select governorate--</option> 

</select> 
</span> 
<br><br><br> 
       <h1><center><strong>Go To-:<a href="www.tricktodesign.com">TrickToDesign</a></strong></center></h1> 
    </body> 
</html>

ajax_category.php

<?php 
include('db.php'); 
if($_POST['governorate_id']) 
{ 
$id=$_POST['governorate_id']; 
$sql=mysql_query("select b.governorate_id,b.governorate_name from governorate a,contry_id b where b.country_id=a.country_id and parent='$id'"); 

while($row=mysql_fetch_array($sql)) 
{ 
$id=$row['governorate_id']; 
$data=$row['governorate_name']; 
echo '<option value="'.$id.'">'.$data.'</option>'; 
} 
} 

?>

如何让第二个下拉列表出现在它的数据是错误，我面对

来源

2013-02-28 dev leb

变化$（ “省 ”）。HTML（HTML）到$（“ 子类别”）。HTML（HTML）

来源

2013-02-28 22:30:57 MIIB

没有MIIB我wnatŧ他省，而不是子类别，但数据不apear如何fx它可以帮助我？ – 2013-02-28 22:38:39

php ajax droplist

的index.php

ajax_category.php

回答

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