Graphviz如何控制边缘

Question

screenshot。我正在寻找右侧的图表，但我得到的是左侧的图表。我是Graphviz的新手。我还必须制作节点1和2，因为我无法模仿右侧的图像。我的终端形状也不完全相同。有人帮助我。我的代码直到现在：

digraph M 
{ 
    style=filled; 
    graph [splines = headport]; 

    START->1 
    1->"Is COUNT\nan even\nnumber?" 
    "Is COUNT\nan even\nnumber?"->"SUM = SUM +\nCOUNT" [label=TRUE] 
    "SUM = SUM +\nCOUNT"->2 
    "Is COUNT\nan even\nnumber?"->2 [label=FALSE] 
    2->"COUNT = COUNT+1" 
    "COUNT = COUNT+1"->"IS COUNT >\n20" 
    "IS COUNT >\n20"->1 [label=FALSE] 
    "IS COUNT >\n20"->STOP[label=TRUE] 


    "Is COUNT\nan even\nnumber?"[shape=diamond] 
    "SUM = SUM +\nCOUNT"[shape=rectangle] 
    "IS COUNT >\n20"[shape=diamond] 
    "COUNT = COUNT+1"[shape=rectangle] 
    1[shape=circle] 
    2[shape=circle] 
    START[shape=record, style="rounded"] 
    STOP[shape=record, style="rounded"] 
} 

Answer 1

我对图表做了一些更改以使您更接近。用于样条的多段线，并将1和2节点的属性更改为更接近您的目标。显然不完美，但希望有足够的帮助，并建议其他方式，你可能会进一步改进，而不需要重新设计。

digraph M 
{ 
    style=filled; 
    graph [splines = headport splines=polyline]; 

    START->1 
    1->"Is COUNT\nan even\nnumber?" 
    "Is COUNT\nan even\nnumber?"->"SUM = SUM +\nCOUNT" [label=TRUE] 
    "SUM = SUM +\nCOUNT"->2 
    "Is COUNT\nan even\nnumber?"->2 [label=FALSE] 
    2->"COUNT = COUNT+1" 
    "COUNT = COUNT+1"->"IS COUNT >\n20" 
    "IS COUNT >\n20"->1 [label=FALSE tailport=e] 
    "IS COUNT >\n20"->STOP[label=TRUE ] 


    "Is COUNT\nan even\nnumber?"[shape=diamond] 
    "SUM = SUM +\nCOUNT"[shape=rectangle] 
    "IS COUNT >\n20"[shape=diamond] 
    "COUNT = COUNT+1"[shape=rectangle headport=n] 
    1[shape=point size="0,0" label=""] 
    2[shape=point size="0,0" label=""] 
    START[shape=record, style="rounded"] 
    STOP[shape=record, style="rounded"] 
}