嗨,我想在XSLT中进行一些聚合。例如,我有以下xml文件。如何在xslt中进行聚合1.0
<?xml version="1.0" encoding="UTF-8" standalone="no" ?>
<reporting:root xmlns:reporting="testing">
<reporting:default0 reporting:type="Portfolio">
<reporting:window reporting:Id="1" reporting:level="0" reporting:name="TEST" reporting:parentId="-1">
<reporting:folio reporting:Id="2" reporting:criteria="0" reporting:level="1" reporting:name="topfolder1" reporting:parentId="1">
<reporting:folio reporting:Id="37" reporting:criteria="0" reporting:level="2" reporting:name="folder2" reporting:parentId="2">
<reporting:folio reporting:Id="38" reporting:criteria="0" reporting:level="3" reporting:name="folder3" reporting:parentId="37">
<reporting:folio reporting:Id="196" reporting:criteria="0" reporting:level="4" reporting:name="folder4" reporting:parentId="38">
<reporting:line reporting:Id="123456" reporting:level="5" reporting:name="element1" reporting:parentId="196" reporting:positionType="0">
<reporting:reference>element1</reporting:reference>
<reporting:number>625</reporting:number>
</reporting:line>
<reporting:line reporting:Id="223456" reporting:level="5" reporting:name="element2" reporting:parentId="196" reporting:positionType="7">
<reporting:reference>element2</reporting:reference>
<reporting:number>475</reporting:number>
</reporting:line>
<reporting:folio reporting:Id="209" reporting:criteria="0" reporting:level="5" reporting:name="delta" reporting:parentId="196">
<reporting:line reporting:Id="223456" reporting:level="6" reporting:name="element2" reporting:parentId="209" reporting:positionType="0">
<reporting:reference>element2</reporting:reference>
<reporting:number>190</reporting:number>
</reporting:line>
</reporting:folio>
</reporting:folio>
</reporting:folio>
</reporting:folio>
</reporting:folio>
<reporting:folio reporting:Id="4" reporting:criteria="0" reporting:level="1" reporting:name="topfolder2" reporting:parentId="1">
<reporting:folio reporting:Id="39" reporting:criteria="0" reporting:level="2" reporting:name="folder24" reporting:parentId="4">
<reporting:folio reporting:Id="40" reporting:criteria="0" reporting:level="3" reporting:name="folder34" reporting:parentId="39">
<reporting:folio reporting:Id="296" reporting:criteria="0" reporting:level="4" reporting:name="folder44" reporting:parentId="40">
<reporting:line reporting:Id="123456" reporting:level="5" reporting:name="element3" reporting:parentId="296" reporting:positionType="0">
<reporting:reference>element3</reporting:reference>
<reporting:number>65525</reporting:number>
</reporting:line>
<reporting:folio reporting:Id="309" reporting:criteria="0" reporting:level="5" reporting:name="delta" reporting:parentId="296">
<reporting:line reporting:Id="2234567" reporting:level="6" reporting:name="element4" reporting:parentId="309" reporting:positionType="0">
<reporting:reference>element4</reporting:reference>
<reporting:number>490</reporting:number>
</reporting:line>
</reporting:folio>
</reporting:folio>
</reporting:folio>
</reporting:folio>
</reporting:folio>
</reporting:window>
</reporting:default0>
</reporting:root>
然后我想在'2级'做一些聚合。即“报告:行”内的任何内容都应返回,并且它是1级和2级父级报告:“folio”也应返回。同样对于level2文件夹的anysubfolder下的相同元素应该聚合为一个。并且还计算总和(数字)。
也没有。在有报告:行标记之前,子作品集可以是200。
所以这个XML我想要得到的结果是:
topfolder,folder2,element1,625
topfolder,folder2,element2,665
topfolder2,folder24,element3,65525
topfolder2,folder24,element4,490
希望我正确解释它。非常感谢您的帮助。
有y你自己试过什么?这似乎是相当基本的xslt;赶上一个教程,你已经超过了你的解决方案的一半。 – Wivani
你能指出一个好的教程吗?我在线上进行了研究,但都使用了xslt 2.0函数。我正在使用xslt 1.0 – ken
http://www.w3schools.com/xsl/ – Wivani