PHP越来越子目录

Question

我试图让所有的XML文件在我的10个子文件夹，并解析这些文件。要做到这一点，我有以下代码：

public static function calculateEAXML ($dir) { 
$dh = opendir($dir); 
$folderNames = array(); 
$arr = array(); 
while (false !== ($folderName = readdir($dh))) { 
    if ($folderName[0] == "." || (substr($folderName, -3) == "zip")) {continue;} 
    $folderNames[] = $folderName; 
    $dom = new DOMDocument; 
    $dom->validateOnParse = true; 
    foreach ($folderNames as $file) 
{ 
    if(is_dir($folderName)){ScanFiles::calculateEAXML($dir);} 
    else{ 
    $df = opendir($dir . $file); 
    while (false !== ($file = readdir($df))) 
    { 
     if ($file == "." || $file == ".." ) {continue;} 
     $dom->Load($dir . $folderName . "/" . $file); 
     $arr[] = XML2Array::createArray($dom); 
    } 
    } 
} 
    return $arr;  
} 
} 

的事情是它只能在一个目录完全忽视了其他解析文件。有没有任何想法如何让它解析所有目录中的所有文件？

Answer 1

有许多与你的脚本的问题，主要是围绕foreach。

1. if(is_dir($folderName))：变量$folderName不存在。我会假设你应该有$file那里。
2. ScanFiles::calculateEAXML($dir);：您再次扫描相同的目录，并且对响应无所作为。
3. $df = opendir($dir . $file);：如果文件不是目录，则试图将其作为目录打开。
4. 你foreach循环是while循环中。

这里是一个企图在修复这些问题：

public static function calculateEAXML($dir) { 
    $dh = opendir($dir); 
    $folderNames = array(); 
    $arr = array(); 

    // Get all files and folders in the current directory 
    while (false !== ($folderName = readdir($dh))) { 
     if ($folderName[0] == "." || (substr($folderName, -3) == "zip")) { 
      continue; 
     } 
     $folderNames[] = $folderName; 
    } 

    foreach ($folderNames as $file) { 
     $filename = $dir . '/' . $file; 
     if(is_dir($filename)){ 
      $arr = array_merge($arr, ScanFiles::calculateEAXML($filename)); 
     } else { 
      $dom = new DOMDocument; 
      $dom->validateOnParse = true; 
      $dom->Load($filename); 
      $arr[] = XML2Array::createArray($dom); 
     } 
    } 
    return $arr;  
} 

Answer 2

这是glob是：

foreach (glob("*.xml") as $filename) { 
    // do sth with the file, $filename holds the current file 
}