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[编辑] - 赏金GoogleApiClient连接的StatusCode SIGN_IN_REQUIRED
我试图连接我与谷歌云端硬盘Android应用程序同步，MP3音频文件。需要使用GoogleDriveAndroidApi和GoogleApiClient连接Google云端硬盘的工作代码/示例（除了下面的链接）。
这个问题已被问了许多次，但他们都没有解决这个问题。所以，我再次问这个。
我第一次使用Google Drive Android API，无法通过“为APP名称选择帐户”屏幕。以下是我做截至目前：
- 试图按照以下网址：
https://developers.google.com/drive/android/get-started
https://github.com/googledrive/android-quickstart
https://www.numetriclabz.com/integrate-google-drive-in-android-tutorial/
使用compile'com.google.android.gms：play-services-drive： 10.0.1' 在我的build.gradle（如果有什么差别）
代码试图至今：
public class ARCBackupActivity extends AppCompatActivity implements GoogleApiClient.ConnectionCallbacks,
GoogleApiClient.OnConnectionFailedListener {
private static final int REQUEST_CODE = 1;
private GoogleApiClient mGoogleApiClient;
private Toolbar mToolbar;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.arc_activity_backup);
mToolbar = (Toolbar) findViewById(R.id.toolbar);
setSupportActionBar(mToolbar);
getSupportActionBar().setDisplayShowTitleEnabled(false);
getSupportActionBar().setDefaultDisplayHomeAsUpEnabled(true);
getSupportActionBar().setDisplayHomeAsUpEnabled(true);
}
@Override
protected void onResume() {
super.onResume();
if (mGoogleApiClient == null) {
// Create the API client and bind it to an instance variable.
// We use this instance as the callback for connection and connection
// failures.
// Since no account name is passed, the user is prompted to choose.
mGoogleApiClient = new GoogleApiClient.Builder(this)
.addApi(Drive.API)
.addScope(Drive.SCOPE_FILE)
.addConnectionCallbacks(this)
.addOnConnectionFailedListener(this)
.build();
}
// Connect the client.
mGoogleApiClient.connect();
}
@Override
protected void onPause() {
if (mGoogleApiClient != null) {
mGoogleApiClient.disconnect();
}
super.onPause();
}
@Override
protected void onActivityResult(final int requestCode, final int resultCode, final Intent data) {
switch (requestCode) {
case REQUEST_CODE:
if (resultCode == Activity.RESULT_OK) {
mGoogleApiClient.connect();
}
break;
}
}
@Override
public void onConnectionFailed(ConnectionResult result) {
// Called whenever the API client fails to connect.
Log.i(Const.DEBUG, "GoogleApiClient connection failed: " + result.toString());
if (!result.hasResolution()) {
// show the localized error dialog.
GoogleApiAvailability.getInstance().getErrorDialog(this, result.getErrorCode(), 0).show();
return;
}
// The failure has a resolution. Resolve it.
// Called typically when the app is not yet authorized, and an
// authorization
// dialog is displayed to the user.
try {
result.startResolutionForResult(this, REQUEST_CODE);
} catch (IntentSender.SendIntentException e) {
Log.e(Const.DEBUG, "Exception while starting resolution activity", e);
}
}
@Override
public void onConnected(Bundle connectionHint) {
Log.d(Const.DEBUG, "API client connected.");
//saveFileToDrive();
}
@Override
public void onConnectionSuspended(int cause) {
Log.d(Const.DEBUG, "GoogleApiClient connection suspended");
}
}
什么是我在这里失踪？任何完整的例子与很好的解释是非常感谢。
让我知道如果我需要提供更多信息以解决这一问题
[编辑1]
如果我添加Plus.API在构建googleApiClient，它解决了被陷在一个循环中的问题选择帐户。但是，Plus.API已被弃用，仅通过使用GoogleApiClient有没有解决方法？
这里是改变的代码：
@Override
protected void onResume() {
super.onResume();
if (mGoogleApiClient != null && mGoogleApiClient.isConnected()) {
Plus.AccountApi.clearDefaultAccount(mGoogleApiClient);
mGoogleApiClient.disconnect();
}
if (mGoogleApiClient == null) {
// Create the API client and bind it to an instance variable.
// We use this instance as the callback for connection and connection
// failures.
// Since no account name is passed, the user is prompted to choose.
mGoogleApiClient = new GoogleApiClient.Builder(this)
.addApi(Drive.API)
.addApi(Plus.API)
.addScope(Drive.SCOPE_FILE)
.addConnectionCallbacks(this)
.addOnConnectionFailedListener(this)
.build();
}
// Connect the client.
mGoogleApiClient.connect();
}
还在寻找实现正确的方式...
“由于没有通过帐户名称，用户会被提示选择” - 是否会发生？如果你获得了这个屏幕，那么它就可以工作。你的错误是，你需要登录到有效的帐户 –
@ cricket_007，是的，我得到的选择帐户屏幕。一旦我选择了该帐户，同一个屏幕就会一次又一次地显示为一个循环。 –
@ cricket_007，你可以检查我编辑的代码，并让我知道什么是正确实施GoogleApiClient的最佳方式？ –