Django外键下拉筛选器

Question

我有一个名为Listing的模型，它基本上是由我的用户发布的职位列表。其中一个字段是一个名为Address的外键（因为用户可以有多个地址）。这里是我的models.py：

class JobListing(models.Model): 
    title = models.CharField(max_length=250) 
    description = models.TextField() 
    customer = models.ForeignKey('CustomerAuth.CustomerProfile') 
    address = models.ForeignKey('CustomerAuth.Address') 

这里是我的forms.py：

class JobListingForm(forms.ModelForm): 
    class Meta: 
     model = JobListing 
     fields = ['title', 'description', 'address', 'customer'] 

最后我views.py的相关部分：

def create_listing(request): 
    form = JobListingForm(request.POST or None) 

    if form.is_valid(): 
     listing = form.save(commit=False) 
     listing.save() 

     current_user = CustomerProfile.objects.get(user=request.user) 
     listing.customer = current_user 
     listing.save() 

     return HttpResponseRedirect('/listings/id/%s' % listing.id) 

    context_dict = {'form': form} 
    return render(request, 'listing/create-listing.html', context_dict) 

因为它目前为当用户从下拉列表中选择一个地址时，它会显示每个人的地址。无论如何，我可以过滤它，以便只显示该用户输入的地址。

Answer 1

forms.py

class JobListingForm(forms.ModelForm): 
    class Meta: 
     model = JobListing 
     fields = ['title', 'description', 'address', 'customer'] 

    def __init__(self, user, *args, **kwargs): 
    super(JobListingForm, self).__init__(*args, **kwargs) 
    self.fields['address'].queryset = Address.objects.filter(user=user) 

在您查看文件

def create_listing(request): 
    user = request.user 
    form = JobListingForm(user, request.POST or None) #pass request.user 

Answer 2

尝试这样的事情

model1.objects.get(pk=1).model2_set.all()