如何获得以下结果？

Question

如何获得以下结果？

输入： -

t1 
-------------- 
col1 col2 col3 
-------------- 
101, abc, 100 
101, xyz, 200 
101, rst, 300 
------------- 

输出： -

101 abc 100 xyz 200 rst 300 

Answer 1

请尝试：

SELECT col1, replace(wm_concat(col2||col3),',', '') FROM t1 GROUP BY col1; 

或

SELECT col1, (SELECT XMLAGG(xmlelement(X, X1.col2||col3)order by X1.col2).extract('//text()') 
      FROM t1 X1 WHERE X1.col1=X.col1) 
FROM t1 X 

Answer 2

这适用于11g并维护项目的顺序。

select LISTAGG (code, ' ') WITHIN GROUP (ORDER BY rn, coln) 
from(

    select code, min(rn) as rn, min(coln) as coln 
    from(
     select col1 as code, rownum rn, 1 as coln from t order by col1, col3 
     union all 
     select col2 as code, rownum rn, 2 as coln from t order by col1, col3 
     union all 
     select col3 as code, rownum rn, 3 as coln from t order by col1, col3 
     ) 
    group by code 
    ) 

Answer 3

尝试用

select col1 || ' ' || listagg(col2 || ' ' || col3, ' ') within group (order by COL3) 
from t1 
group by col1;