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我有一个带有条件列及其值的数据框,我有一个仅包含条件的数据框,并且我想通过匹配条件来提取它们的值。R在数据框的不同行中匹配字符串
df1:
Name Style Price Style Price Style Price
Gary A 100 AB 300 B 200
Johnson AB 200 B 700 A 300
Marsha AC 300 C 500 A 400
Watson A 400 B 200 AB 500
Emma C 500 B 100 BC 600
df1 = structure(list(Name = c("Gary", "Johnson", "Marsha", "Watson",
"Emma"), Style = c("A", "AB", "AC", "A", "C"), Price = c(100L,
200L, 300L, 400L, 500L), Style.1 = c("AB", "B", "C", "B", "B"
), Price.1 = c(300L, 700L, 500L, 200L, 100L), Style.2 = c("B",
"A", "A", "AB", "BC"), Price.2 = c(200L, 300L, 400L, 500L, 600L
)), .Names = c("Name", "Style", "Price", "Style.1", "Price.1",
"Style.2", "Price.2"), class = "data.frame", row.names = c(NA,
-5L))
df2:
Name Style
Gary AB
Johnson A
Marsha C
Watson B
Emma BC
df2 = structure(list(Name = c("Gary", "Johnson", "Marsha", "Watson",
"Emma"), Style = c("AB", "A", "C", "B", "BC")), .Names = c("Name",
"Style"), class = "data.frame", row.names = c(NA, -5L))
desired output:
Name Style Price
Gary AB 300
Johnson A 300
Marsha C 500
Watson B 200
Emma BC 600
我不知道如何在条件不同的列中匹配它们。感谢您的帮助。
遗憾是什么如果名称与样式,图案,格式不同,是否在value.name中添加了所有名称? –
@PeterChung您是否指'Style','style'等?在这种情况下,'measure = patterns(“ Ss] tyle“,”Price“),' – akrun
我的意思是标题应该是样式价格格式价格格式价格,所以measure = patterns(”样式“,”价格“,”样式“,”格式“) –