#include <iostream>
using namespace std;
int main()
{
int firstvalue = 5, secondvalue = 15;
int * p1, * p2;
p1 = &firstvalue; // p1 = address of firstvalue
p2 = &secondvalue; // p2 = address of secondvalue
*p1 = 10; // value pointed by p1 = 10
*p2 = *p1; // value pointed by p2 = value pointed by p1
p1 = p2; // p1 = p2 (value of pointer is copied)
*p1 = 20; // value pointed by p1 = 20
cout << "firstvalue is " << firstvalue << endl;
cout << "secondvalue is " << secondvalue << endl;
return 0;
}
输出为10 20.不应该输出20 20吗?我在想什么,因为它确实P1 = P2因此既p1和p2具有相同的地址,然后将其设置为p1指出值= 20,因此,他们的假设值更改为20当两个值具有相同的地址时
你的回答让完美的感官。非常感谢。 – 14K 2013-05-14 07:18:17