我试图在销毁它们时清除敌人的健康值,并且出现错误“没有重载函数的实例...”与参数列表匹配如果我有以下几点:从for循环中删除向量中的元素 - C++
upgradeHealth.erase(inner)
这似乎只能接受这样的事情:
upgradeHealth.erase(upgradeHealth.begin())
我所需要的元素,在内部被擦除的位置,使之与刚刚摧毁了敌人的匹配。这里是for循环:
for (outer = 0; outer < bullets.size(); outer++)
{
for (inner = 0; inner < upgrades.size(); inner++)
{
if (upgrades[inner]->HitTest(bullets[outer]))
{
upgradeHealth[inner] -= 1;
bullets.erase(outer--);
multiplier += 0.01;
hasHit = true;
multiplierTime = 0;
cout << upgradeHealth[inner] << endl;
if (upgradeHealth[inner] == 0)
upgradeHealth.erase(inner), upgrades.erase(inner), score += 100 * multiplier;
break;
}
}
}
尝试“upgradeHealth.begin()+内部”而不是 – Hacketo 2014-12-04 15:05:12
我曾考虑过这样做,但掩盖了它,但它的工作原理非常感谢你! – StallMar 2014-12-04 15:15:57