MySQL错误，未知原因

我一直在阅读这个查询现在约20分钟，我看不出它有什么问题。MySQL错误，未知原因

SELECT SQL_CALC_FOUND_ROWS addressbook_people.first_name, 
     addressbook_people.last_name      , 
     addressbook_people.preferred_name    , 
     addressbook_companies3.name      , 
     addressbook_people.url       , 
     addressbook_groups5.name       , 
     addressbook_people.telephone1     , 
     addressbook_people.telephone2     , 
     addressbook_people.telephone3     , 
     addressbook_people.email1      , 
     addressbook_people.email2      , 
     addressbook_people.fax1       , 
     addressbook_people.fax2       , 
     root_countries13.name       , 
     root_territories14.name       , 
     root_cities15.name        , 
     addressbook_people.address1      , 
     addressbook_people.zip_postal1     , 
     addressbook_people.po_box      , 
     root_countries19.name       , 
     root_territories20.name       , 
     root_cities21.name        , 
     addressbook_people.address2      , 
     addressbook_people.zip_postal2 
FROM  addressbook_people 
WHERE (
        (
          addressbook_people.first_name  LIKE '%a%' 
        OR  addressbook_people.last_name  LIKE '%a%' 
        OR  addressbook_people.preferred_name LIKE '%a%' 
        OR  addressbook_companies3.name  LIKE '%a%' 
        OR  addressbook_people.url   LIKE '%a%' 
        OR  addressbook_groups5.name   LIKE '%a%' 
        OR  addressbook_people.telephone1  LIKE '%a%' 
        OR  addressbook_people.telephone2  LIKE '%a%' 
        OR  addressbook_people.telephone3  LIKE '%a%' 
        OR  addressbook_people.email1   LIKE '%a%' 
        OR  addressbook_people.email2   LIKE '%a%' 
        OR  addressbook_people.fax1   LIKE '%a%' 
        OR  addressbook_people.fax2   LIKE '%a%' 
        OR  root_countries13.name    LIKE '%a%' 
        OR  root_territories14.name   LIKE '%a%' 
        OR  root_cities15.name    LIKE '%a%' 
        OR  addressbook_people.address1  LIKE '%a%' 
        OR  addressbook_people.zip_postal1 LIKE '%a%' 
        OR  addressbook_people.po_box   LIKE '%a%' 
        OR  root_countries19.name    LIKE '%a%' 
        OR  root_territories20.name   LIKE '%a%' 
        OR  root_cities21.name    LIKE '%a%' 
        OR  addressbook_people.address2  LIKE '%a%' 
        OR  addressbook_people.zip_postal2 LIKE '%a%' 
       ) 
     ) 
     LEFT JOIN addressbook_companies AS addressbook_companies3 
     ON  addressbook_people.company_id = addressbook_companies3.id 
     LEFT JOIN addressbook_groups AS addressbook_groups5 
     ON  addressbook_people.group_id = addressbook_groups5.id 
     LEFT JOIN root_countries AS root_countries13 
     ON  addressbook_people.country1 = root_countries13.id 
     LEFT JOIN root_territories AS root_territories14 
     ON  addressbook_people.territory1 = root_territories14.id 
     LEFT JOIN root_cities AS root_cities15 
     ON  addressbook_people.city1 = root_cities15.id 
     LEFT JOIN root_countries AS root_countries19 
     ON  addressbook_people.country2 = root_countries19.id 
     LEFT JOIN root_territories AS root_territories20 
     ON  addressbook_people.territory2 = root_territories20.id 
     LEFT JOIN root_cities AS root_cities21 
     ON  addressbook_people.city2 = root_cities21.id 
ORDER BY LTRIM(addressbook_people.url)DESC 
LIMIT 0, 10

这是我的数据表过滤器的输出。所以忽略了我正在寻找像“一”

我使用phpMyAdmin，通过Web管理控制台执行的查询的SQL时，我收到以下错误

1064的事实 - 你有一个您的SQL语法错误;检查

对应于你的MySQL服务器版本正确的语法使用附近的线54

我检查了线“LEFT JOIN addressbook_companies AS addressbook_companies3 ON 地址”的手册，它是我加入的开始。我没有看到问题..有人可以帮忙吗？我从来没有用过SQL。

来源

2011-08-18 rlemon

没有或许在Web管理控制台中的查询长度的限制，不是吗？这是一个很长的查询。 –

我想看看这个查询需要多少时间在1.000.000行的表上执行，这并不是那么多:) – mkk

它实际上并没有那么糟糕。现在我有6000行，它在几分之一秒内执行。它是ajax结果过滤的一部分。我看到很少的延迟，所以我没有实际测试过它。 – rlemon

你需要你的WHERE子句之前做你JOIN小号

来源

2011-08-18 20:03:56

他们已经在'where'之后 – hughes

@嘘，是的，他们是我在发布后立即注意到我的漏洞。 –

只是为了澄清：连接之后的地方，而不是之前。 –

MySQL错误，未知原因

1064的事实 - 你有一个您的SQL语法错误;检查

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