我有一个完美的工作这个SELECT子句:Postgres的复杂选择视图
SELECT
"Aspectos"."ID" AS "Aspecto Normativo ID",
"Aspectos"."Aspecto" AS "Aspecto Normativo",
"Fatores"."ID", "Fatores"."Fator" AS "Fator Normativo",
"Diagnostico"."Vinculo_Final",
"Fatores_1"."ID",
"Fatores_1"."Fator" AS "Fator Determinativo",
"Aspectos_1"."ID" AS "Aspecto Determinativo ID",
"Aspectos_1"."Aspecto" AS "Aspecto Determinativo",
Count("Itens"."ID") AS "No Itens",
Count("Itens"."ID") AS "Pri"
FROM "Diagnostico" INNER JOIN ("Aspectos" AS "Aspectos_1"
INNER JOIN (("Fontes" INNER JOIN "Itens" ON "Fontes"."ID" = "Itens"."Fonte")
INNER JOIN ("Fatores" AS "Fatores_1"
INNER JOIN ("Aspectos"
INNER JOIN ("Vinculos"
INNER JOIN "Fatores"
ON "Vinculos"."Fator_Normativo" = "Fatores"."ID")
ON ("Aspectos"."ID" = "Fatores"."Aspecto")
AND ("Aspectos"."ID" = "Fatores"."Aspecto"))
ON "Fatores_1"."ID" = "Vinculos"."Fator_Determinativo")
ON "Itens"."ID" = "Vinculos"."Item")
ON "Aspectos_1"."ID" = "Fatores_1"."Aspecto")
ON "Diagnostico"."ID" = "Vinculos"."Diagnostico_ID"
GROUP BY "Aspectos"."ID", "Aspectos"."Aspecto",
"Fatores"."ID", "Fatores"."Fator",
"Diagnostico"."Vinculo_Final",
"Fatores_1"."ID",
"Fatores_1"."Fator",
"Aspectos_1"."ID",
"Aspectos_1"."Aspecto"
ORDER BY "Aspectos"."ID", "Aspectos_1"."ID",
"Fatores"."Fator", "Fatores_1"."Fator";
但是当我尝试创建一个视图与此相同的选择我收到的Thuis错误:
ERROR: column "ID" specified more than one time
任何人都可以帮助我做到这一点。 谢谢
你能告诉我们你的CREATE VIEW语句吗? – 2013-02-20 16:19:46