2015-11-19 61 views
0

嗨,我有我的应用程序我有添加3D触控快速操作的问题,我的问题是,当我的应用程序是不是在多任务处理,然后在我的应用程序无法打开共享表已任何人一个想法如何解决这个问题,我的代码问题只是在信息视图和问题快速行动工作很好的共享快速行动。3D快速行动分享功能不工作时,在应用程序关闭

// AppDelegate.swift

进口的UIKit 进口MessageUI

@UIApplicationMain 类的AppDelegate:UIResponder,UIApplicationDelegate,MFMailComposeViewControllerDelegate {

var window: UIWindow? 

enum QuickActionType : String { 
    case viewControllerInfo = "com.example.infoView" 
    case share = "com.example.share" 
    case problem = "com.example.problem" 

} 

func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool { 
    var QuickAction = false 

    if let shortcutItem = launchOptions?[UIApplicationLaunchOptionsShortcutItemKey] as? UIApplicationShortcutItem{ 
     QuickAction = true 
     handleQuickAction(shortcutItem) 
    } 

    return !QuickAction 

} 

func application(application: UIApplication, performActionForShortcutItem shortcutItem: UIApplicationShortcutItem, completionHandler: (Bool) -> Void) { 
    let handledQuickAction = handleQuickAction(shortcutItem) 
    completionHandler(handledQuickAction) 

} 

func mailComposeController(controller: MFMailComposeViewController, didFinishWithResult result: MFMailComposeResult, error: NSError?) { 
    if error != nil { 
     print(error?.localizedDescription) 
    } 

    self.window?.rootViewController?.dismissViewControllerAnimated(true, completion: nil) 

} 


func applicationWillResignActive(application: UIApplication) { 
    // Sent when the application is about to move from active to inactive state. This can occur for certain types of temporary interruptions (such as an incoming phone call or SMS message) or when the user quits the application and it begins the transition to the background state. 
    // Use this method to pause ongoing tasks, disable timers, and throttle down OpenGL ES frame rates. Games should use this method to pause the game. 
} 

func applicationDidEnterBackground(application: UIApplication) { 
    // Use this method to release shared resources, save user data, invalidate timers, and store enough application state information to restore your application to its current state in case it is terminated later. 
    // If your application supports background execution, this method is called instead of applicationWillTerminate: when the user quits. 
} 

func applicationWillEnterForeground(application: UIApplication) { 
    // Called as part of the transition from the background to the inactive state; here you can undo many of the changes made on entering the background. 
} 

func applicationDidBecomeActive(application: UIApplication) { 
    // Restart any tasks that were paused (or not yet started) while the application was inactive. If the application was previously in the background, optionally refresh the user interface. 
} 

func applicationWillTerminate(application: UIApplication) { 
    // Called when the application is about to terminate. Save data if appropriate. See also applicationDidEnterBackground:. 
} 

func handleQuickAction(shortcutItem: UIApplicationShortcutItem) -> Bool { 

    var handled = false 

    if let shortCutType = QuickActionType.init(rawValue: shortcutItem.type){ 
     let rootNavigationViewController = window!.rootViewController as? UINavigationController 
     let rootViewController = rootNavigationViewController?.viewControllers.first as UIViewController? 

     rootNavigationViewController?.popToRootViewControllerAnimated(false) 

     switch shortCutType { 

      // Quick Action Info 

     case .viewControllerInfo: 
      handled = true 
      rootViewController?.performSegueWithIdentifier("infoView", sender: nil) 


     case .share: 
      handled = true 

      let shareItems = ["hello world"] 

      let activityViewController = UIActivityViewController(activityItems: shareItems, applicationActivities: nil) 

      self.window?.rootViewController?.presentViewController(activityViewController, animated: true, completion: nil) 

      // Quick Action Problem 

     case .problem: 
      handled = true 

      let mailController = MFMailComposeViewController() 
      mailController.mailComposeDelegate = self 
      mailController.setToRecipients(["[email protected]"]) 
      mailController.setSubject("App Bug") 
      mailController.setMessageBody("(Your Problem) 

      self.window?.rootViewController?.presentViewController(mailController, animated: true, completion: nil) 

     } 
    } 

    return handled 

} 

}

+0

任何人都可以帮助我吗? – chris188

回答

0

尝试添加轻微在处理你的快速行动之前延迟,看看是否帮助。当我执行我的快速行动时,我发现他们不会在没有很小的延迟的情况下100%可靠地工作。我目前使用0.5秒。你可以做这样的事情(在OBJ-C):

[self.performSelector:@selector(doAction:) withObject:obj afterDelay:0.5]; 

或SWIFT:

self.performSelector("doAction:", withObject: obj, afterDelay: 0.5) 

这可能会或可能不会在你的情况有所帮助,但它在我没有和我提起了关于它的雷达,我还没有听说过。

0

嘿,你需要显示的ViewController在当前视图控制器的顶部尝试。例如,这是一个简单的扩展在你的AppDelegate上添加这个。眼下

extension UIWindow { 

func visibleViewController() -> UIViewController? { 
    if let rootViewController: UIViewController = self.rootViewController { 
     return UIWindow.getVisibleViewControllerFrom(rootViewController) 
    } 
    return nil 
} 

class func getVisibleViewControllerFrom(vc:UIViewController) -> UIViewController { 

    if vc.isKindOfClass(UINavigationController.self) { 

     let navigationController = vc as! UINavigationController 
     return UIWindow.getVisibleViewControllerFrom(navigationController.visibleViewController!) 

    } else if vc.isKindOfClass(UITabBarController.self) { 

     let tabBarController = vc as! UITabBarController 
     return UIWindow.getVisibleViewControllerFrom(tabBarController.selectedViewController!) 

    } else { 

     if let presentedViewController = vc.presentedViewController { 

      return UIWindow.getVisibleViewControllerFrom(presentedViewController.presentedViewController!) 

     } else { 

      return vc; 
     } 
    } 
}} 

可以检查可见的ViewController像

self.window?.visibleViewController()?.presentViewController(yourviewcontroller, animated: true, completion: nil) 

我希望这会帮助你。

+0

isKindOfClass?你是认真的吗? :D这是迄今为止我所见过的最类似objc的代码。你从哪里学到的? ;) – Ben

+0

是的,因为你可以看到它的工作原理来检查当前可见的视图控制器 – BilalReffas

+0

也许,但代码风格是可怕的 – Ben

相关问题