的Silverlight C＃的LINQ to XML

Question

我工作的一个Silverlight Web应用程序，类似于XML的工作原理：

<?xml version="1.0" encoding="UTF-8" ?> 
<ProjectList> 
    <Type>web</Type> 
    <Project> 
     <Id>1</Id> 
     <Name>test web project</Name> 
     <Description>test web project</Description> 
     <ScreenshotList> 
      <Screenshot> 
       <Path>screen1.jpg</Path> 
       <Description>This a description of screen 1</Description> 
      </Screenshot> 
      <Screenshot> 
       <Path>screen2.jpg</Path> 
       <Description>This a description of screen 2</Description> 
      </Screenshot> 
      <Thumb>noThumb.jpg</Thumb> 
     </ScreenshotList> 
    </Project> 
</ProjectList> 

我想创建一个新的对象为XML中的每个项目元素。我有一个名为project的类，其中包含id，name，description，thumb和所有屏幕截图的列表字段。

我当前的LINQ代码如下所示：

var projects = from project in xDoc.Root.Elements("Project") 
         select new Project(
            Int32.Parse(project.Element("Id").Value, CultureInfo.InvariantCulture), 
            project.Element("Name").Value, 
            project.Element("Description").Value, 
            project.Element("ScreenshotList").Element("Thumb").Value 
            ); 

反正对我来说，很容易得到的截图，这一个查询内项目的实例将它们添加到列表中？

编辑 - 添加项目构造

public Project(int id, string name, string description, string thumbPath) 
{ 
    this.id = id; 
    this.name = name; 
    this.description = description; 
    this.thumbPath = thumbPath; 
} 

Answer 1

喜欢的东西：

var projects = from project in xDoc.Root.Elements("Project") 
        let list = project.Element("ScreenshotList") 
        select new Project(
         (int) project.Element("Id"), 
         (string)project.Element("Name"), 
         (string)project.Element("Description"), 
         (string)list.Element("Thumb"), 
         from scr in list.Elements("Screenshot") 
         select new Screenshot(
          (string)scr.Element("Path"), 
          (string)scr.Element("Description") 
         ) 
        ); 

基于类型，如：

class Project { 
    public int Id { get; set; } 
    public string Name { get; set; } 
    public string Description { get; set; } 
    public string Thumb { get; set; } 
    public List<Screenshot> Screenshots { get; private set; } 
    public Project(int id, string name, string description, string thumb, 
      IEnumerable<Screenshot> screenshots) { 
     this.Id = id; 
     this.Name = name; 
     this.Description = description; 
     this.Thumb = thumb; 
     this.Screenshots = screenshots == null ? new List<Screenshot>() 
       : new List<Screenshot>(screenshots); 
    } 
} 
class Screenshot { 
    public string Path { get; set; } 
    public string Description { get; set; } 
    public Screenshot(string path,string description) { 
     this.Path = path; 
     this.Description = description; 
    } 
} 

Answer 2

好了，你还没有显示的项目构造是什么样的......它让你在截图作为IEnumerable<Screenshot>通过？如果是这样，它应该很容易......是这样的：

var projects = 
    from p in xDoc.Root.Elements("Project") 
    select new Project(Int32.Parse(project.Element("Id").Value, 
            CultureInfo.InvariantCulture), 
         p.Element("Name").Value, 
         p.Element("Description").Value, 
         p.Element("ScreenshotList") 
         .Element("Thumb").Value, 
         p.Element("ScreenshotList") 
         .Elements("Screenshot") 
         .Select(ss => 
          new Screenshot(ss.Element("Path").Value, 
              ss.Element("Description").Value)) 
        ); 

（我已经重新格式化了一下，以避免滚动。）