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我想实现一个交互式文本菜单来简化我的一些较大的代码执行,并且无法弄清楚如何将它构造成功能完整。现在我有一个主菜单,2个子菜单和一个退出功能。我需要子菜单来执行我所拥有的特定代码(我将在后面介绍这些代码),但是我以一种方式编写它,其中选项1和2总是会进入我的两个子菜单,无论我在哪里在我的菜单中。如果我选择了1作为第一个选项,那么我会遇到其他选项的第一个或第二个选项,那么对此进行编码的最佳方法是什么?我显然需要摆脱1和2的常数值,但我不确定如何按照我需要的方式使其工作。Python正在运行的交互式菜单
import time, sys, os
# Main definition - constants
menu_actions = {}
##Menu Functions
def main_menu():
os.system('cls')
print ""
print 30 * "-", "MENU", 30 * "-"
print "1. Batch Deployment"
print "2. Single Deployment"
print "3. List Tickets"
print "0. Exit/Quit"
print 66 * "-"
print ""
choice = raw_input(" Make a selection from the menu >> ")
exec_menu(choice)
def batch_menu():
os.system('cls')
print "Batch Deployment\n"
print "1. Run All In Progress Sonic Deployments"
print "9. Back"
print "0. Quit"
print ""
choice = raw_input(" >> ")
exec_menu(choice)
return
def ticket_menu():
os.system('cls')
print "Choose Task to Deploy...\n"
print "9. Back"
print "0. Quit"
print ""
choice = raw_input(" >> ")
exec_menu(choice)
return
def exec_menu(choice):
os.system('cls')
ch = choice.lower()
if ch == '':
menu_actions['main_menu']()
else:
try:
menu_actions[ch]()
except KeyError:
print "Invalid selection, please try again.\n"
time.sleep(3)
menu_actions['main_menu']()
return
def back():
menu_actions['main_menu']()
# Menu definition
menu_actions = {
'main_menu': main_menu,
'1': batch_menu,
'2': ticket_menu,
'9': back,
'0': exit, }
# Menu Logic
if __name__ == "__main__":
# Launch main menu
main_menu()