Youtube通过URLRequest上传？

Question

我试图通过YouTube API上传视频。我可以验证一切正常，并制定请求就好，但请求的正文与我遇到的二进制视频数据有关。

什么是正确的方式来编码文件数据并将其添加到urlRequest的主体？

我最好的猜测是：

public function getFileStreamBytes(fileName:String):String{ 

var byteArray:ByteArray = new ByteArray(); 
var returnString:String = ""; 

var file:File = new File(fileName); 
var fileStream:FileStream = new FileStream(); 
fileStream.open(file,FileMode.READ); 
fileStream.position = 0; 
fileStream.readBytes(byteArray); 

byteArray.position = 0; 
for(var i:Number = 0; byteArray.bytesAvailable > 0; i++){ 
    returnString += byteArray.readUTF(); 

} 
return returnString; 
} 

这将返回一个400错误的请求响应

Answer 1

我只是遇到了一个非常类似的问题，终于得到了一个答案（信贷计算器用户deadrunk）。事实证明，如果您通过URLRequest发送二进制数据，则必须手动将其格式化为POST数据。看看下面的代码：

//*** FORMAT POST DATA ***// 
var myByteArray:ByteArray = new ByteArray; //Data to be uploaded 
var myData:ByteArray = new ByteArray; 
var myBoundary:String = ""; 
var stringData:String; 
var i:uint; 

for (i = 0; i < 0x20; ++i) myBoundary += String.fromCharCode(uint(97+Math.random()*25)); 
myData.writeShort(0x2d2d); //-- 
myData.writeUTFBytes(myBoundary); 
myData.writeShort(0x0d0a); //\r\n 
stringData = 'Content-Disposition: form-data; name="fieldName"; filename="filename.txt"'; 
for (i = 0; i < stringData.length; i++) myData.writeByte(stringData.charCodeAt(i)); 
myData.writeShort(0x0d0a); //\r\n 
stringData = 'Content-Type: application/octet-stream'; //Change me! 
myData.writeShort(0x0d0a); //\r\n 
myData.writeShort(0x0d0a); //\r\n 
for (i = 0; i < stringData.length; i++) myData.writeByte(stringData.charCodeAt(i)); 
myData.writeBytes(myByteArray, 0, myByteArray.length); 
myData.writeShort(0x0d0a); //\r\n 
myData.writeShort(0x2d2d); //-- 
myData.writeUTFBytes(myBoundary); 
myData.writeShort(0x2d2d); //-- 

//*** SEND REQUEST ***// 
var uploadRequest:URLRequest = new URLRequest("http://127.0.0.1/upload.php"); 
uploadRequest.method = URLRequestMethod.POST; 
uploadRequest.contentType = 'multipart/form-data; boundary=' + myBoundary; 
uploadRequest.data = myData 
uploadRequest.requestHeaders.push(new URLRequestHeader('Cache-Control', 'no-cache')); 

var uploader:URLLoader = new URLLoader; 
uploader.dataFormat = URLLoaderDataFormat.BINARY; 
uploader.load(uploadRequest); 

基本上你添加一个“;边界= [边界线]”参数的内容类型，然后格式化您的要求，例如：

--[boundary string] 
Content-Disposition: form-data; name="[name of the form field]"; filename="[filename you want the server to see]" 
Content-Type: [ideally your data's actual content type] 

[your binary data] 
--[boundary string]-- 

我希望帮助！