2013-02-13 99 views
0

您好,我需要一些使用explode和array_combine形成阵列的帮助。使用PHP array_combine&爆炸与多维数组

我想结合使用爆炸的结果下面的两个数组(qty和fooddesc)。我试图使数组数组的关键和fooddesc数组使用数组结合的值,但无法获得正确的语法,所以我中止了。

我似乎无法弄清楚如何做到这一点。可能我只需要改变查询数据的方式,所以我根本不需要使用爆炸?这让我疯狂。

我正在组成数组来包含n餐包含食物数量和它们的描述的膳食计划,以便我可以很容易地将数据从数组中排除到我的html中。

这里是我的代码和阵列输出:

// Begin Meal Plan 
$sql = "SELECT notes, mealdesc, optdesc, group_concat(qty) as qty, group_concat(fooddesc SEPARATOR ',') as fooddesc 
    FROM plan p 
    INNER JOIN mealplan mp 
    ON mp.planid = p.id 
    INNER JOIN meal m 
    ON m.id = mp.mealid 
    INNER JOIN foodmeal fm 
    ON fm.mealid = m.id 
    INNER JOIN food f 
    ON f.id = fm.foodid 
    where userid = 2 
    GROUP by mealdesc 
    order by mealdesc"; 

$result = mysqli_query($link, $sql); 
if (!$result) 
{ 
    echo 'Error'; 
    exit(); 
} 

// Fetch meal data 
while($row = mysqli_fetch_array($result)){ 
$meals[$row['mealdesc']] = array('optdesc' => $row['optdesc'], 'qty' => explode(",",  $row['qty']), 'fooddesc' => explode(",", $row['fooddesc'])); 
$notes = $row['notes']; 
} 
// End Meal Plan 

这里是阵列,它产生:(我修剪这表明仅仅是第一餐尽量简短)

Array 
(
    [Meal 1] => Array 
     (
      [optdesc] => upon awakening 
      [qty] => Array 
       (
        [0] => 1 
        [1] => 6 
        [2] => 1/2 cup 
        [3] => 2 slices 
        [4] => 1 piece 
        [5] => 1 cup 
       ) 

      [fooddesc] => Array 
       (
        [0] => egg 
        [1] => egg whites 
        [2] => oatmeal 
        [3] => wheat toast 
        [4] => fruit 
        [5] => berries 
       ) 

     ) 

编辑 再次尝试array_combine并使用count和for循环来组合qty和food desc,然后使用unset删除旧的qty/fooddesc数组。

我不知道这是否是最好的解决方案,但它的工作原理。 :)认为我只是回答了我自己的问题。

// Fetch meal data 
while($row = mysqli_fetch_array($result)){ 
$meals[$row['mealdesc']] = array('optdesc' => $row['optdesc'], 'qty' => explode(",",  $row['qty']), 'fooddesc' => explode(",", $row['fooddesc'])); 
$notes = $row['notes']; 
} 

$j = count($meals); 
for($i = 1; $i <= $j ; $i++) 
{ 
$meals['Meal '.$i][food] = array_combine($meals['Meal '.$i]['qty'], $meals['Meal '.$i]['fooddesc']); 
unset($meals['Meal '.$i]['qty']); 
unset($meals['Meal '.$i]['fooddesc']); 
} 
// End Meal Plan 

这给了我:

Array 
(
    [Meal 1] => Array 
     (
      [optdesc] => upon awakening 
      [food] => Array 
       (
        [1] => egg 
        [6] => egg whites 
        [1/2 cup] => oatmeal 
        [2 slices] => wheat toast 
        [1 piece] => fruit 
        [1 cup] => berries 
       ) 

     ) 

    [Meal 2] => Array 
     (
      [optdesc] => 3 hours later 
      [food] => 
     ) 

回答

0
array_combine(
array_values($meals['Meal 1']['qty']), 
array_values($meals['Meal 1']['fooddesc']) 
) 

aray_combine()使用的键第一个参数,第二个参数值,这里我们使用值第一阵列,作为联合数组的键。

+0

感谢阿卡姆。如果我不知道确切的吃饭次数,我该怎么做?每餐计划可能会有所不同。有些可能有4个,有些可能有8个。 – guyinjersey 2013-02-13 14:50:42

0

再次尝试array_combine并使用count和for循环来组合数量和食物desc,然后使用unset删除旧的qty/fooddesc数组。

我不知道这是否是最好的解决方案,但它的工作原理。 :)认为我只是回答了我自己的问题。

// Fetch meal data 
while($row = mysqli_fetch_array($result)){ 
$meals[$row['mealdesc']] = array('optdesc' => $row['optdesc'], 'qty' => explode(",",  $row['qty']), 'fooddesc' => explode(",", $row['fooddesc'])); 
$notes = $row['notes']; 
} 

$j = count($meals); 
for($i = 1; $i <= $j ; $i++) 
{ 
$meals['Meal '.$i][food] = array_combine($meals['Meal '.$i]['qty'], $meals['Meal '.$i]['fooddesc']); 
unset($meals['Meal '.$i]['qty']); 
unset($meals['Meal '.$i]['fooddesc']); 
} 
// End Meal Plan 

这给了我:

Array 
(
    [Meal 1] => Array 
     (
      [optdesc] => upon awakening 
      [food] => Array 
       (
        [1] => egg 
        [6] => egg whites 
        [1/2 cup] => oatmeal 
        [2 slices] => wheat toast 
        [1 piece] => fruit 
        [1 cup] => berries 
       ) 

     ) 

    [Meal 2] => Array 
     (
      [optdesc] => 3 hours later 
      [food] => 
     )