JavaScript的正则表达式匹配

Question

我有一些变量

var jdbcurl="jdbc:oracle:thin:%2F%2Finnova:1521%3BServiceName%3Dorcl%3BMaxPooledStatements%3D20%3BCatalogOptions%3D0%3BBatchPerformanceWorkaround%3Dtrue" 

alert(jdbcurl.match(/:[\d]+/)); //gives me :1521 

我怎样才能得到jdbc:oracle:thin，innova，1521 & orcl出jdbcurl变种？

更新

您可以尝试here（如果需要）

Answer 1

var jdbcurl="jdbc:oracle:thin:%2F%2Finnova:1521%3BServiceName%3Dorcl%3BMaxPooledStatements%3D20%3BCatalogOptions%3D0%3BBatchPerformanceWorkaround%3Dtrue" 
var myregex = /([a-z:]+):%2F%2F([a-z]+):(\d+)%3BServiceName%3D([a-z]+)%3BMaxPooledStatements%3D20%3BCatalogOptions%3D0%3BBatchPerformanceWorkaround%3Dtrue/ 
var matches = myregex.exec(jdbcurl); 
// jdbc:oracle:thin is in matches[1], innova is in matches[2], 1521 is in matches[3], and orcl is in matches[4] 

Answer 2

我说jdbcurl.split(/(%..)/)将是一个开始 - 然后你可以进一步检查是否保留他们的元素或将它们分割。

Answer 3

先使用decodeURIComponent（），然后使用分号分割。不要让自己难过！

Answer 4

你可能正则表达式维护过程中，如果你要解析多个URL也尝试一下本作更好的可读性网址：

var jdburl = unescape("jdbc:oracle:thin:%2F%2Finnova:1521%3BServiceName%3Dorcl%3BMaxPooledStatements%3D20%3BCatalogOptions%3D0%3BBatchPerformanceWorkaround%3Dtrue"); 

var myRegExp = new Regexp('([a-z:]+)://(\\w+):(\\d+);ServiceName=(\\w+);'); 

var matches = myRegExp.exec(jdburl);