2013-05-07 116 views
1

我想使用仅具有服务器URL的Android API从http服务器获取目录中包含的所有文件的列表。我怎样才能实现它?如何从http服务器列出目录中的所有文件?

顺便说一句 - 我有权访问服务器,如果有什么需要设置。

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由于这与Android无关,并且无法将代码添加到服务器,因此请使用更多相关标签。 – CommonsWare 2013-05-07 11:06:08

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http://stackoverflow.com/questions/11561608/how-to-get-list-of-files-directories-of-an-directory-url-in-java – 2013-05-07 11:07:44

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除非服务器允许或实现它,你可以“T。 – 2013-05-07 11:14:12

回答

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你必须写一个PHP脚本来扫描服务器上的所有文件,例如像:

<?php 
$directory = '/path/to/files'; 

if (! is_dir($directory)) { 
    exit('Invalid diretory path'); 
} 

$files = array(); 

foreach (scandir($directory) as $file) { 
    $files[] = $file; 
} 

var_dump($files); // YOU HAVE TO WRITE THE OUTPUT AS JSON OR XML 
?> 

与Android,你必须只调用这个脚本,如:

class RequestTask extends AsyncTask<String, String, String>{ 

    @Override 
    protected String doInBackground(String... uri) { 
     HttpClient httpclient = new DefaultHttpClient(); 
     HttpResponse response; 
     String responseString = null; 
     try { 
      response = httpclient.execute(new HttpGet(uri[0])); 
      StatusLine statusLine = response.getStatusLine(); 
      if(statusLine.getStatusCode() == HttpStatus.SC_OK){ 
       ByteArrayOutputStream out = new ByteArrayOutputStream(); 
       response.getEntity().writeTo(out); 
       out.close(); 
       responseString = out.toString(); 
      } else{ 
       //Closes the connection. 
       response.getEntity().getContent().close(); 
       throw new IOException(statusLine.getReasonPhrase()); 
      } 
     } catch (ClientProtocolException e) { 
      //TODO Handle problems.. 
     } catch (IOException e) { 
      //TODO Handle problems.. 
     } 
     return responseString; 
    } 

    @Override 
    protected void onPostExecute(String result) { 
     super.onPostExecute(result); 
     //Do anything with response.. 
    } 
} 

(要执行的AsyncTask:

new RequestTask().execute("URI to PHP Script"); 

希望有所帮助!

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我不明白,ASyncTask需要一个URI,你写,PHP脚本必须通过? – Mariusz 2013-05-08 08:18:59

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