For循环与阵列不打印正确的结果

Question

新的js，代码如下。在这里，我无法打印正确的结果。我认为+ "names[i]"这部分代码有问题。

var names = ["aha","mk", "jk","hk","fhf"]; 
for (i=1;i<=names.length;i++){ 
    console.log("I know someone called "+ "names[i]"); 
    } 

Answer 1

省略名称[i]周围的引号。 它应该是：所有的

var names = ["aha","mk", "jk","hk","fhf"]; 
for (i=1;i<=names.length;i++){ 
    console.log("I know someone called "+ names[i]); 
} 

Answer 2

var names = ["aha","mk", "jk","hk","fhf"]; 
for (i=1;i<=names.length;i++){ 
    console.log("I know someone called "+ names[i]); 
    } 

名[i]是一个字符串了。

Answer 3

• FIRST：正如大家一直说，你不要放置names[i]双引号内，因为它是一个定义的变量的引用。

• 第二：在您的for循环的** ** 声明i<=names.length，但它应该是i<names.length。你的方式会一路走到6，这太高了。

• 第三：除了第二个错误，你也必须改变names[i]到names[i--]，因为i<names.length仍然会达到5和1过高了一些，开始用的。

Answer 4

不加引号使用names[i]它是一个expression提供你的价值观

，您可以利用的es6模板串

var names = ["aha","mk", "jk","hk","fhf"]; 
    for (i=0;i<=names.length-1;i++){ 
     console.log(`I know someone called ${names[i]}`); 
    } 

Answer 5

请检查名称[I]不应该保持双引号，并将i值更改为0

var names = ["aha","mk", "jk","hk","fhf"]; 
for (i=0;i<=names.length;i++) 
{ 
     console.log("I know someone called "+ names[i]); 
} 

Answer 6

我认为这是工作正确 您需要删除=符号并设置i = 0

var names = ["aha","mk", "jk","hk","fhf"]; 
     for (i=0;i<names.length;i++){ 
     console.log("I know someone called "+ names[i]); 
    }