2017-04-02 63 views
1

如果我的问题听起来很愚蠢,我很抱歉,我还是Java新手。我要告诉你这段代码:如何添加一个mouselistener在JFrame的其他事物之下?

public class Window extends JFrame{ 


    private static final long serialVersionUID = -2139430787087799923L; 

    private TransparentJPanel mousepanel; 

    public Window(int width, int height, String title, Game game) { 
     super(title); 
     HandlerClass handler = new HandlerClass(); 
     mousepanel = new TransparentJPanel(); 
     mousepanel.addMouseListener(handler); 

     setPreferredSize(new Dimension(width,height)); 
     setMaximumSize(new Dimension(width,height)); 
     setMinimumSize(new Dimension(width,height)); 
     setDefaultCloseOperation(EXIT_ON_CLOSE); 
     setResizable(false); 

     setVisible(true); 
     add(game);  <-- here I add the game 
     add(mousepanel); <-- here I add the panel with the mouselistener 
     game.start(); 
    } 
} 

的TransparentJPanel类:

private class TransparentJPanel extends JPanel { 
    private static final long serialVersionUID = 8855609189172945035L; 

    TransparentJPanel() { 
     super() ; 
     this.setOpaque(false) ; 
     this.setLayout(null) ; 
    } 
} 

当我第一次加入游戏,游戏显示了和鼠标侦听器不工作,但当我首先添加jpanel时,游戏不会显示,但是mouselistener起作用。 这里是我的HandlerClass类:

private class HandlerClass implements MouseListener { 
    public void mouseClicked(MouseEvent event) { 
     System.out.println(String.format("Clicked at %d,%d", event.getX(), event.getY())); 
    } 

    public void mouseEntered(MouseEvent e) { 
     int x = e.getX(); 
     int y = e.getY(); 
     System.out.println("Mouse Entered frame at X: " + x + " - Y: " + y); 

    } 
    public void mouseExited(MouseEvent e) { 
     int x = e.getX(); 
     int y = e.getY(); 
     System.out.println("Mouse Exited frame at X: " + x + " - Y: " + y); 

    } 
    public void mousePressed(MouseEvent e) { 
     int x = e.getX(); 
     int y = e.getY(); 
     System.out.println("Mouse Pressed frame at X: " + x + " - Y: " + y); 

    } 

    public void mouseReleased(MouseEvent e) { 
     int x = e.getX(); 
     int y = e.getY(); 
     System.out.println("Mouse Released at X: " + x + " - Y: " + y); 

    } 

} 

所以,这是我的问题。 请帮忙。

+0

是'游戏'一个JPanel类吗? –

+0

号游戏是游戏循环等可运行的类下面是Game.java的全码:https://pastebin.com/cpsMSMxY –

+0

'JFrame'使用'默认情况下,只允许单个组件BorderLayout'一次显示在5个可用位置之一。你有什么理由需要分开面板吗?让游戏面板充当“MouseListener”是否更合乎逻辑? – MadProgrammer

回答

0

解决方案结果很简单!的

,而不是创建的鼠标监听器面板,可以将MouseListener的加入到游戏中的对象,即如下

public Window(int width, int title, String title, Game game) { 
    super(title); 
    HandlerClass handler = new HandlerClass(); 

    setPreferredSize(new Dimension(width,height)); 
    setMaximumSize(new Dimension(width,height)); 
    setMinimumSize(new Dimension(width,height)); 
    setDefaultCloseOperation(EXIT_ON_CLOSE); 
    setResizable(false); 

    setVisible(true); 
    add(game, BorderLayout.CENTER); 
    game.addMouseListener(handler);  
    game.start(); 
} 

希望这有助于!

+0

感谢您的回答,但它仍然无法正常工作。当我启动它时,只显示一个灰色屏幕,但是mouselistener起作用。当我切换它们时,显示游戏,但是mouselistener一开始只工作了一秒,因为我在控制台看到鼠标进入了框架。 –

+0

在这种情况下,我建议将游戏画布包装在JPanel中,并将两个面板(游戏面板和鼠标面板)添加到框架中。 –

+0

你是什么意思?你可以解释吗? im kinnda new –

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