访问控制服务抛出异常

我在我的包services.xml文件设置3个简单的控制器，就像这样：访问控制服务抛出异常

 http://symfony.com/schema/dic/services/services-1.0.xsd">
 <parameters> 
    <parameter key="wsh_lapi.content.class">Wsh\LapiBundle\Controller\ContentController</parameter> 
    <parameter key="wsh_lapi.users.class">Wsh\LapiBundle\Controller\UserController</parameter> 
    <parameter key="wsh_lapi.alerts.class">Wsh\LapiBundle\Controller\AlertController</parameter> 
</parameters> 

<services> 
    <service id="wsh_lapi.content" class="%wsh_lapi.content.class%"> 
     <argument type="service" id="service_container"/> 
    </service> 
    <service id="wsh_lapi.users" class="%wsh_lapi.users.class%"> 
     <argument type="service" id="service_container"/> 
    </service> 
    <service id="wsh_lapi.alerts" class="%wsh_lapi.alerts.class%"> 
     <argument type="service" id="service_container"/> 
    </service> 
</services>

但是，当我试图让在AlertController wsh_lapi.users服务，像这样：

class AlertController extends Controller { protected $container;

 function __construct(Container $container) 
{ 
    $this->container = $container; 
} 

public function postAlert($appIdToken, $securityToken, $searchParams) 
{ 
    // first let see if user not allready registered 
    $em = $this->getDoctrine()->getManager(); 
    //$user = $this->container->get('wsh_lapi.users')->getUser($appIdToken, $securityToken); 
    if($this->container->has('wsh_lapi.users')) { 
     // this throws FatalErrorExecption 
     $userService = $this->container->get('wsh_lapi.users'); 
    } 
    // check if that alert does not exist allready 
    $alertRepo = $em->getRepository('WshLapiBundle:Alert'); 
    // todo: do checking 

    // create new alert object 
    $alert = new Alert(); 
    $alert->setUser($user); 
    $alert->setSearchQueryParams($searchParams); 
    $em->persist($alert); 
    $em->flush(); 

    return $alert; 

}

}

我得到一个奇怪的错误：

FatalErrorException：错误：类“的Symfony \分量\调试\异常\ ContextErrorE xception'找不到在/Users/bard/Projects/LavelAPI/src/Wsh/LapiBundle/Controller/UserController.php线82

我不知道该怎么做，第82行是UserController的结束，与外观像这样：

class UserController extends Controller { protected $container;

 function __construct(Container $container) 
{ 
    $this->container = $container; 
} 

/** 
* Register new user or return existing one based on given AppId token 
* @param $appIdToken unique user token generated in client app 
* @return User 
*/ 
public function registerDevice($appIdToken) 
{ 
    // first let see if user not allready registered 
    $em = $this->getDoctrine()->getManager(); 
    $repo = $em->getRepository('WshLapiBundle:User'); 
    $user = $repo->findOneByAppId($appIdToken); 
    if(!$user) { 
     // user not found create new one 
     $user = new User(); 
     $user->setAppId($appIdToken); 
     $em->persist($user); 
     $em->flush(); 
    } 
    return $user; 

} 

/** 
* Removes user from database so he's token will no longer be authenticated 
* 
* @param $appIdToken 
* @param $securityToken 
* @return string 
* @throws \Symfony\Component\HttpKernel\Exception\NotFoundHttpException 
*/ 
public function unRegisterDevice($appIdToken, $securityToken) 
{ 
    $user = $this->getUser($appIdToken, $securityToken); 
    $em = $this->getDoctrine()->getManager(); 

    $em->remove($user); 
    $em->flush(); 
    return "OK"; 
} 

public function getUser($appIdToken, $securityToken) 
{ 
    // first let see if user not allready registered 
    $em = $this->getDoctrine()->getManager(); 
    $repo = $em->getRepository('WshLapiBundle:User'); 
    $user = $repo->findOneByAppId($appIdToken); 
    if(!$user) { 
     throw $this->createNotFoundException('No user with appIdToken: '.$appIdToken.' has been found'); 
    } 
    // check security token 
    if(!$user->checkSecurityToken($securityToken)) { 
     throw new \Exception('Request not authorized. Tokens does not match'); 
    } 
    return $user; 
}

}

来源

2013-07-01 Bartosz Rychlicki

原来的probles用的功能，我wsh_lapi.users服务控制器名称“的getUser”。可能它与Symfony基本控制器有某种碰撞。在我简单地改变函数名称后，它开始工作。

来源

2013-07-02 08:20:27

访问控制服务抛出异常

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