接收作业：未取得结果

Question

我想从作业中返回组成员列表，但从Receive-Job中得不到任何结果。我想获取包含数组的变量或传递给新数组。

下面的示例代码。我如何获得Receive-Job以返回$objGroupMembers中的数据？

Start-Job -Name 'GroupName' -ScriptBlock { 
    Get-PSSnapin -Registered | Add-PSSnapin; 

    $aryProperties = @(
     "SamAccountName" 
     "employeeid" 
     "firstname" 
     "lastname" 
     "email" 
     "title" 
     "department" 
    ) 

    $objGroupMembers = Get-QADGroupMember -Identity "GroupName" -Indirect -SizeLimit 0 -DontUseDefaultIncludedProperties -IncludedProperties $aryProperties | Select-Object $aryProperties 
} 

Answer 1

你的工作没有返回任何东西。基本上，工作就像在后台运行一个新的控制台。任何输出到该控制台都可以使用Receive-Job进行检索。但在你的情况下，你将结果分配给你的变量，就是这样。以下应该有所帮助：

Start-Job -Name 'GroupName' -ScriptBlock { 
    Get-PSSnapin -Registered | Add-PSSnapin; 

    $aryProperties = @(
    "SamAccountName" 
    "employeeid" 
    "firstname" 
    "lastname" 
    "email" 
    "title" 
    "department" 
    ) 


    $objGroupMembers = Get-QADGroupMember -Identity "GroupName" -Indirect -SizeLimit 0 -DontUseDefaultIncludedProperties -IncludedProperties $aryProperties | Select-Object $aryProperties 

    $objGroupMembers 
}