PHP从多维数组中找到值，然后将它们放在一个数组中

我有一个数组，其中包含来自数据库的一组信息，但其中一些数据是重复的，只有数组最深处的值为1 。例如：PHP从多维数组中找到值，然后将它们放在一个数组中

[0] => Array(['id'] => 1 , ['name'] => "First Array" , ['more'] => "stuff") 
[1] => Array(['id'] => 2 , ['name'] => "Second Array" , ['more'] => "stuff1") 
[2] => Array(['id'] => 2 , ['name'] => "Second Array" , ['more'] => "stuff2") 
[3] => Array(['id'] => 3 , ['name'] => "Third Array" , ['more'] => "stuff3") 
[4] => Array(['id'] => 3 , ['name'] => "Third Array" , ['more'] => "stuff4")

我想要做的就是用相同的[“身份证”]字段中的任何阵列到阵列的阵列，而不是[“更多”]。例如：

[0] => Array(['id'] => 1 , ['name'] => "First Array" , ['more'] => "stuff") 
[1] => Array(['id'] => 2 , ['name'] => "Second Array" , ['more'] => Array([0] => "stuff1" , [1] => "stuff2")) 
[2] => Array(['id'] => 2 , ['name'] => "Third Array" , ['more'] => Array([0] => "stuff3" , [1] => "stuff4"))

我试图做这几种方法，但我可以得到最接近的是这将会把所有的[“更多”]值到1门阵列这样的功能：

[0] => Array(['id'] => 1 , ['name'] => "First Array" , ['more'] => "stuff") 
[1] => Array(['id'] => 2 , ['name'] => "Second Array" , ['more'] => Array([0] => "stuff1" , [1] => "stuff2" , [2] => "stuff3" , [3] => "stuff4"))

这就是从这样的功能：

<?php 
private function compress_duplicates($a = array()) { 
    $diff_key = array_diff_key($a , array_unique($a)); 
    $first_key = array_shift(array_keys($diffkey)); 
    $array["id"] = $diff_key[$first_key]["id"]; 
    $array["name"] = $diff_key[$first_key]["name"]; 
    foreach($diff_key as $term) { 
     $array["more"][] = $term["more"]; 
    } 
    return $array; 
} 
?>

基本上我问的：我怎样才能找到一个多维数组复制，然后将每个这些重复的到自己的阵列？

来源

2011-09-04 Ben

$result = array(); 
foreach ($array as $elem) { 
    if (isset($result[$elem['id']])) { 
     $result[$elem['id']]['more'] = array_merge((array)$result[$elem['id']]['more'], 
                array($elem['more'])); 
    } else { 
     $result[$elem['id']] = $elem; 
    } 
}

任选接着$result = array_values($result)，如果你想重置$result阵的钥匙。

来源

2011-09-04 22:50:22 deceze

PHP从多维数组中找到值，然后将它们放在一个数组中

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