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如何加载WPF的主要形式,以便单独的线程在窗体处于房间状态时从数据库获取数据? (拖能/移动)WPF加载,以便我可以移动表格
我知道这是可能与您的主要形式打开一个新的窗口,像这样:
Private Sub openOrderWindow()
Dim OrderWindow As Orders = New Orders
OrderWindow.ShowDialog()
End Sub
Private Sub ButtonImport_Click(sender As System.Object, e As System.Windows.RoutedEventArgs) Handles ButtonImport.Click
Dim iThread As System.Threading.Thread = New System.Threading.Thread(AddressOf openOrderWindow)
iThread.SetApartmentState(System.Threading.ApartmentState.STA)
iThread.Start()
ListViewOrderDetail.Focus()
' Me.Close()
End Sub
因为我用“的ShowDialog”
但在主窗口我不能打电话的ShowDialog
我曾尝试:
Private Sub AccessDBFilling()
ListViewDataGrid.ItemsSource = Nothing
accessdblist = Nothing
accessdblist = accessdb.GetFromAccess()
ListViewDataGrid.ItemsSource = accessdblist
End Sub
Private Sub refresh()
ListViewDataGrid.Dispatcher.Invoke(New Action(AddressOf AccessDBFilling))
End Sub
Private Sub Window_Loaded(sender As System.Object, e As System.Windows.RoutedEventArgs) Handles MyBase.Loaded
iThread = New System.Threading.Thread(AddressOf refresh)
iThread.SetApartmentState(System.Threading.ApartmentState.STA)
iThread.Start()
End Sub
我试图把MyBase.ShowDialog()
和.Show()
和.9000+其他事情
唯一的好处我已经得到了使用单独的线程从DATABSE负载我可以看到屏幕的时候了(中作为反对它是一个透明的盒子,直到它加载),但我不能移动它或最小化它
有没有办法让它移动,而它加载?
行动loadFromDb = AccessDBFilling说“表达不产生价值'但无论如何,我是因为你写的内容才能工作,所以我会接受这个答案 – 2012-04-27 11:45:33