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我是Spring安全新手，我正在使用Spring安全性4.我遵循一个教程开始，但每次我都会收到找到的NoSuchBeanDefinition错误。 不知何故，我已经尝试了所有在网络和计算器上提到的建议，但无法弄清楚。Spring安全性：获取NoSuchBean异常错误
以下是我的应用程序与Spring-Security合作的片段。
弹簧的security.xml
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-4.1.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-4.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<!-- enable use-expressions -->
<http auto-config="true" use-expressions="true">
<intercept-url pattern="/admin**" access="hasRole('ROLE_ADMIN')" />
<!-- access denied page -->
<access-denied-handler error-page="/403" />
<form-login
login-page="/login"
default-target-url="/welcome"
authentication-failure-url="/login?error"
username-parameter="username"
password-parameter="password" />
<logout logout-success-url="/login?logout" />
<!-- enable csrf protection -->
<csrf />
</http>
<authentication-manager>
<authentication-provider user-service-ref="userDetailsService" >
<password-encoder hash="bcrypt" />
</authentication-provider>
</authentication-manager>
</beans:beans>
Web.xml中
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:web="java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
xsi:schemaLocation="java.sun.com/xml/ns/javaee java.sun.com/xml/ns/javaee /web-app_3_0.xsd"
>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/appServlet/spring-security.xml </param-value>
</context-param>
<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<!-- Processes application requests -->
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/appServlet/servlet-context.xml, /WEB-INF/spring/appServlet/spring-security.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<!-- Spring Security -->
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<session-config>
<tracking-mode>COOKIE</tracking-mode>
</session-config>
的servlet-context.xml的
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans
xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-4.0.xsd">
<annotation-driven />
<resources mapping="/resources/**" location="/resources/" />
<beans:bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value=".jsp" />
</beans:bean>
<!-- Testing Database MySQL Local System -->
<beans:bean id="dataSource"class="org.apache.commons.dbcp.BasicDataSource"
destroy-method="close">
<beans:property name="driverClassName" value="com.mysql.jdbc.Driver" />
<beans:property name="url" value="jdbc:mysql://127.0.0.1:3306/tutorzest" />
<beans:property name="username" value="root" />
<beans:property name="password" value="root" />
</beans:bean>
<!-- Hibernate 4 SessionFactory Bean definition -->
<beans:bean id="hibernate4AnnotatedSessionFactory"
class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<beans:property name="dataSource" ref="dataSource" />
<beans:property name="annotatedClasses">
<beans:list>
<beans:value>com.spring.model.User</beans:value>
<beans:value>com.spring.model.UserRole</beans:value>
</beans:list>
</beans:property>
<beans:property name="hibernateProperties">
<beans:props>
<beans:prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect
</beans:prop>
<beans:prop key="hibernate.show_sql">true</beans:prop>
</beans:props>
</beans:property>
</beans:bean>
<beans:bean id="transactionManager" class="org.springframework.orm.hibernate4.HibernateTransactionManager">
<beans:property name="sessionFactory" ref="hibernate4AnnotatedSessionFactory" />
</beans:bean>
<beans:bean id="userDao" class="com.spring.dao.UserDaoImpl">
<beans:property name="sessionFactory" ref ="hibernate4AnnotatedSessionFactory"/>
</beans:bean>
<beans:bean id="userDetailsService" class="com.spring.service.MyUserDetailsService">
</beans:bean>
<context:component-scan base-package="com.spring.controller" />
<tx:annotation-driven transaction-manager="transactionManager"/>
</beans:beans>
** ** MyUserDetailsService
@Service("userDetailsService")
public class MyUserDetailsService implements UserDetailsService {
//get user from the database, via Hibernate
@Autowired
private UserDao userDao;
@Transactional(readOnly=true)
@Override
public UserDetails loadUserByUsername(final String username)
throws UsernameNotFoundException {
com.xpedia.spring.model.User user = userDao.findByUserName(username);
List<GrantedAuthority> authorities =
buildUserAuthority(user.getUserRole());
return buildUserForAuthentication(user, authorities);
}
// Converts com.mkyong.users.model.User user to
// org.springframework.security.core.userdetails.User
private User buildUserForAuthentication(com.xpedia.spring.model.User user,
List<GrantedAuthority> authorities) {
return new User(user.getUsername(), user.getPassword(),
user.isEnabled(), true, true, true, authorities);
}
private List<GrantedAuthority> buildUserAuthority(Set<UserRole> userRoles)
Set<GrantedAuthority> setAuths = new HashSet<GrantedAuthority>();
// Build user's authorities
for (UserRole userRole : userRoles) {
setAuths.add(new SimpleGrantedAuthority(userRole.getRole()));
}
List<GrantedAuthority> Result =
new ArrayList <GrantedAuthority> (setAuths);
return Result;
}
}
执行我收到以下错误后：
org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'org.springframework.security.filterChains': Cannot resolve reference to bean 'org.springframework.security.web.DefaultSecurityFilterChain#0' 'org.springframework.security.authentication.dao.DaoAuthenticationProvider#0': Cannot resolve reference to bean 'userDetailsService' while setting bean property 'userDetailsService'; nested exception is org.springframework.beans.factory.NoSuchBeanDefinitionException: No bean named 'userDetailsService' is defined
我可能会缺少一些xml配置。但是经过这么多的尝试才发现，我发现它很困难。请帮助我。
您的安全配置是根应用上下文，而另一种是孩子上下文。您在根/父上下文中从子上下文引用UserSetailService。孩子可以引用父上下文bean，但是它不能以其他方式工作。解决这个问题的一种方法是仅在您的servlet上下文中扫描控制器，并扫描根环境中除controller之外的所有内容。 –
也从Dispatcher Servlet初始化参数中删除安全上下文。 –