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客户端代码片段。基本上它从标准输入中读取消息并将消息发送到服务器。如何清理InputStream而不关闭它?
public static void main(String[] args) {
try (Socket socket = new Socket("localhost", 1200)) {
OutputStreamWriter writer = new OutputStreamWriter(socket.getOutputStream(), StandardCharsets.US_ASCII);
Scanner scanner = new Scanner(System.in);
for (String msg = scanner.nextLine(); !msg.equals("end"); msg = scanner.nextLine()) {
writer.write(msg + "\n");
writer.flush();
}
} catch (IOException e) {
e.printStackTrace();
}
}
Server code snippet。从流中打印消息。从客户端
public void run() {
try (InputStreamReader reader = new InputStreamReader(this.socket.getInputStream(), StandardCharsets
.US_ASCII)) {
StringBuilder builder = new StringBuilder();
for (int c = reader.read(); c != -1; c = reader.read()) {
builder.append((char) c);
if ((char) c == '\n')
System.out.print(builder);
}
} catch (IOException e) {
e.printStackTrace();
}
}
输入:
Text1
Text2
服务器输出:
Text1
Text1
Text2
的问题,我面对的是服务器输出不刚刚收到的消息,而且之前的所有消息。
问题:如何在不关闭的情况下重置'clean'InputStream
。如果这是不可能的,什么是首选的解决方案?
愚蠢的错误:)。 TNX –