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我需要制作如下所示的json参数。iPhone:为服务器请求格式化json时出现问题
最终输出应该是,
{"submissionTime":"\/Date(1331549630849)\/",
"statusId":"0",
"answers":[{"answer":"Yes","qid":167},{"answer":"Hello","qid":168}],
"participantId":"16369",
"token":"t_ikHOXVjlcsSb9Tfdn5RaO54JGQobHodUD5881SKevxy63jwLxe8ZPQvXYss4pR"}
我试图让这种格式。我得到了时间,状态,参与和令牌。没关系。但是,我在制作“answers”数组时遇到了问题。
我使用下面的代码来制作如下所示的答案json格式。
NSArray *answerkeys = [NSArray arrayWithObjects:@"answer", @"qid",nil];
NSString *qID = [NSString stringWithFormat:@"%d", [questionidArray objectAtIndex:i] ]; // for loop
NSArray *objectkeys = [NSArray arrayWithObjects:value, qID,nil];
NSString *answerjsonRequest = [pSr makeJSONObject:objectkeys :answerkeys];
answerjsonRequest = [(NSString *)answerjsonRequest stringByReplacingOccurrencesOfString:@"\n" withString:@""];
[textvaluesArray addObject:[NSString stringWithFormat:@"%@", answerjsonRequest]];
并且输出如下所示。
(
"{ \"answer\" : \"Hello\", \"qid\" : \"220421824\"}",
"{ \"answer\" : \"How are you\", \"qid\" : \"115781136\"}"
)
但是,当我将所有在一个像下面的最终输出,
NSString *jsonRequest = [pSr makeJSONObject:[NSArray arrayWithObjects: participantID, (NULL!=textvaluesArray)?textvaluesArray:@"0", [NSString stringWithFormat:@"%d", statusID], subTime, [appDelegate getSessionToken], nil] :[NSArray arrayWithObjects:@"participantId", @"answers", @"statusId", @"submissionTime", @"token", nil] ];
The final json result is this.
{
"submissionTime" : "\/Date(1331566698)\/",
"token" : "t_hvYoxifLQhxEKfyw1CAgVtgOfA3DjeB9jZ3Laitlyk9fFdLNjJ4Cmv6K8s58iN",
"participantId" : "16371",
"answers" : [
"{ \"answer\" : \"Hello\", \"qid\" : \"220421824\"}",
"{ \"answer\" : \"Hello\", \"qid\" : \"115781136\"}"
],
"statusId" : "0"
}
但是,这不是一个我想要什么。我预期的JSON输出是上面提到的最重要的。我尝试了很多方法,但无法做到这一点。有人可以帮助我解决这个问题以获得准确的JSON输出吗?
谢谢!
您能否也请解释您如何致电并解决问题? – Getsy 2012-03-12 17:27:29
'jsonRequest = [jsonRequest replaceEscapedQuotes];' – bdparrish 2012-03-12 17:28:59
很有帮助,非常感谢! – Getsy 2012-03-12 18:33:21