合并2个不同类型的列表为1

Question

我有2个不同类型的列表，我想按日期分组，然后合并每个日期的2个列表。

我的2清单看起来像这样。

List<Payment> payments = new List<Payment> 
{ 
    new Payment{Date = '2014-01-01 12:23:52', PaymentSum = 300}, 
    new Payment{Date = '2014-01-01 12:23:53', PaymentSum = 100}, 
    new Payment{Date = '2014-01-02 12:23:52', PaymentSum = 300}, 
} 

List<Invoice> invoices = new List<Invoice> 
{ 
    new Invoice{Date = '2014-01-01 12:20:32', InvoiceSum= 300}, 
    new Invoice{Date = '2014-01-01 12:21:53', InvoiceSum= 200}, 
    new Invoice{Date = '2014-01-02 12:24:52', InvoiceSum= 300}, 
} 

我想结果是这个样子：提前

List<NewItem> newItems= new List<NewItem> 
{ 
    new NewItem{Date = '2014-01-01', InvoiceSum= 500, PaymentSum = 400}, 
    new NewItem{Date = '2014-01-02', InvoiceSum= 300, PaymentSum = 300}, 
} 

谢谢！

Answer 1

这里是第一选择所有不同日期的方法：

var dateSums = payments 
    .Select(p => p.Date.Date) 
    .Concat(invoices.Select(i => i.Date.Date)) 
    .Distinct() 
    .Select(d => new 
    { 
     Date = d, 
     InvoiceSum = invoices 
      .Where(i => i.Date.Date == d) 
      .Sum(i => i.InvoiceSum), 
     PaymentSum = payments 
      .Where(i => i.Date.Date == d) 
      .Sum(i => i.PaymentSum) 
    }); 

请注意，我正在使用Date.Date，因为该属性是DateTime wi时间部分。

Answer 2

你既可以创建一个第三类

class ThirdType { 
    public Invoice Invoice { get; set; } 
    public Payment Payment { get; set; } 
} 

或最终使用的元组列出

List<Tuple<Date, Invoice, Payment>>();