的R - 为固定值添加随机值未在列重复矩阵和行

Question

及彼很大的帮助，随机矩阵没有重复的行和列（Fixed values not repeated over column and row）我有一个关于修改另一个问题之后。

所以，先下手做了什么：我想与随机的行和列的矩阵无需在每个重复（行方向和列）明智的。再次感谢这里本有很大的帮助是jdobres代码（https://stackoverflow.com/users/6436545/jdobres）我最终使用：

# number of rows and columns 
n <- 10 

# create ordered rows and columns 
ordered.by.row <- matrix(1:n, n, n) 
ordered.by.col <- matrix(1:n, n, n, byrow = T) 

# offset the rows and columns relative to each other. 
# no row or column has a repeated value, but the values are still ordered 
offset <- (ordered.by.row + ordered.by.col) %% n + 1 

# shuffle the columns, then shuffle the rows, this produces a randomized matrix 
# 'shuffle.row' is the final, randomized matrix 
set.seed(1222) # change this to change randomization 
shuffle.col <- offset[,sample(1:n, n, replace = F)] 
shuffle.row <- shuffle.col[sample(1:n, n, replace = F), ] 

# verify solution 
any(apply(shuffle.row, 1, function(r)any(duplicated(r)))) # FALSE 
any(apply(shuffle.row, 2, function(r)any(duplicated(r)))) # FALSE 


> # create ordered rows and columns 
ordered.by.row <- matrix(1:n, n, n) 
ordered.by.col <- matrix(1:n, n, n, byrow = T) 

# offset the rows and columns relative to each other. 
# no row or column has a repeated value, but the values are still ordered 
offset <- (ordered.by.row + ordered.by.col) %% n + 1 

# shuffle the columns, then shuffle the rows, this produces a randomized matrix 
# 'shuffle.row' is the final, randomized matrix 
set.seed(1222) # change this to change randomization 
shuffle.col <- offset[,sample(1:n, n, replace = F)] 
shuffle.row <- shuffle.col[sample(1:n, n, replace = F), ] 

# verify solution 
any(apply(shuffle.row, 1, function(r)any(duplicated(r)))) # FALSE 
any(apply(shuffle.row, 2, function(r)any(duplicated(r)))) # FALSE 

     [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] 
[1,] 1 10 6 9 2 8 3 5 7  4 
[2,] 3 2 8 1 4 10 5 7 9  6 
[3,] 7 6 2 5 8 4 9 1 3 10 
[4,] 9 8 4 7 10 6 1 3 5  2 
[5,] 10 9 5 8 1 7 2 4 6  3 
[6,] 2 1 7 10 3 9 4 6 8  5 
[7,] 8 7 3 6 9 5 10 2 4  1 
[8,] 6 5 1 4 7 3 8 10 2  9 
[9,] 5 4 10 3 6 2 7 9 1  8 
[10,] 4 3 9 2 5 1 6 8 10  7 

但是我现在，我想我的第一行有问题（可以说排1,2,3）按特定顺序修复。不过，我需要新的行4至10再次随机分组并没有（关于1-3行也没有重复）重复！

所以，比如我有3行是这样的：

 [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] 
[1,] 8 7 3 6 9 5 10 2 4  1 
[2,] 6 5 1 4 7 3 8 10 2  9 
[3,] 5 4 10 3 6 2 7 9 1  8 

但接下来的7行我想随机但不重复（在任何行或列）值，而不改变第一行...

任何想法？我无法弄清楚如何排除那些我想留下来（第1-3行），但仍然没有在其他行和列的重复...

您的帮助将再次非常感谢！

编辑：

非常感谢您Moody_Mudskipper您的帮助！这是什么解决方案看起来就像用我的（假的）数据：

mat<-as.matrix(first.rows) 
nkeep <- 3 
mat_shuffled <- mat[c(1:nkeep,sample((nkeep+1):nrow(mat),replace=FALSE)),] 

    [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] 
row1 1 4 7 6 5 3 2 8 9 10 
row2 10 7 3 2 1 4 5 9 8  6 
row3 9 2 4 3 5 7 10 1 6  5 
     10 7 9 6 8 2 5 4 3  1 
     1 10 8 4 7 3 5 2 6  9 
     10 6 4 1 8 3 7 2 5  9 
     2 5 7 8 9 6 1 3 4 10 
     2 1 10 4 8 9 3 6 5  7 
     8 5 3 2 4 1 10 7 6  9 
     6 1 5 4 2 10 3 8 7  9 

还得感谢你！

查阅Constructing a randomised matrix with no duplicates but fixed partial input一个解决方案费尔南多也保持VALUES列UNIQUE

Answer 1

将这项工作？

mat <- matrix(1:100,10) 
nkeep <- 3 
mat_shuffled <- mat[c(1:nkeep,sample((nkeep+1):nrow(mat),replace=FALSE)),] 
#  [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] 
# [1,] 1 11 21 31 41 51 61 71 81 91 
# [2,] 2 12 22 32 42 52 62 72 82 92 
# [3,] 3 13 23 33 43 53 63 73 83 93 
# [4,] 6 16 26 36 46 56 66 76 86 96 
# [5,] 10 20 30 40 50 60 70 80 90 100 
# [6,] 7 17 27 37 47 57 67 77 87 97 
# [7,] 4 14 24 34 44 54 64 74 84 94 
# [8,] 5 15 25 35 45 55 65 75 85 95 
# [9,] 9 19 29 39 49 59 69 79 89 99 
# [10,] 8 18 28 38 48 58 68 78 88 98